**Staircase**

### Problem Statement :

Staircase detail: This is a staircase of size n = 4: # ## ### #### Its base and height are both equal to n. It is drawn using # symbols and spaces. The last line is not preceded by any spaces. Write a program that prints a staircase of size n. Function Description: Complete the staircase function in the editor below. staircase has the following parameter(s): int n: an integer Print: Print a staircase as described above. Input Format: A single integer, n , denoting the size of the staircase. Constraints: 0 < n <= 100. Output Format: Print a staircase of size n using # symbols and spaces. Note: The last line must have 0 spaces in it. .

### Solution :

` ````
Solution in C :
In C :
void staircase(int n) {
for(int i=0;i<n;i++)
{
for(int j=0;j<n-i-1;j++)
{
printf(" ");
}
for(int k = i; k >= 0; k--)
{
printf("#");
}
printf("\n");
}
}
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int n;
cin >> n;
string str(n, ' ');
for (int i = 1; i <= n; ++i) {
str[n-i] = '#';
cout << str << endl;
}
return 0;
}
In Python3 :
n=int(input())
m=" "
t=1
while n>n-n:
print((n-1)*m+t*("#"))
n=n-1
t=t+1
In Java :
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int N = sc.nextInt();
for(int i=1;i<=N;i++) {
for(int j=1;j<=N-i;j++){
System.out.print(" ");
}
for(int k=0;k<i;k++)
System.out.print("#");
System.out.println();
}
}
}
```

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