# Staircase

### Problem Statement :

```Staircase detail:
This is a staircase of size n = 4:

#
##
###
####

Its base and height are both equal to n. It is drawn using # symbols and spaces. The last line is not preceded by any spaces.

Write a program that prints a staircase of size n.

Function Description:
Complete the staircase function in the editor below.

staircase has the following parameter(s):
int n: an integer

Print:
Print a staircase as described above.

Input Format:
A single integer, n , denoting the size of the staircase.

Constraints:
0 < n <= 100.

Output Format:
Print a staircase of size n using # symbols and spaces.

Note: The last line must have 0 spaces in it.

.```

### Solution :

```                            ```Solution in C :

In C :

void staircase(int n) {
for(int i=0;i<n;i++)
{
for(int j=0;j<n-i-1;j++)
{
printf(" ");
}

for(int k = i; k >= 0; k--)
{
printf("#");
}

printf("\n");
}

}

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {

int n;
cin >> n;
string str(n, ' ');

for (int i = 1; i <= n; ++i) {
str[n-i] = '#';
cout << str << endl;
}
return 0;
}

In Python3 :

n=int(input())
m=" "
t=1
while n>n-n:
print((n-1)*m+t*("#"))
n=n-1
t=t+1

In Java :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

int N = sc.nextInt();
for(int i=1;i<=N;i++) {
for(int j=1;j<=N-i;j++){
System.out.print(" ");
}
for(int k=0;k<i;k++)
System.out.print("#");

System.out.println();

}

}

}```
```

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