Problem Statement :

Staircase detail:
    This is a staircase of size n = 4:


Its base and height are both equal to n. It is drawn using # symbols and spaces. The last line is not preceded by any spaces.

Write a program that prints a staircase of size n.

Function Description:
           Complete the staircase function in the editor below.

staircase has the following parameter(s):
    int n: an integer

    Print a staircase as described above.

Input Format:
    A single integer, n , denoting the size of the staircase.

   0 < n <= 100.

Output Format:
    Print a staircase of size n using # symbols and spaces.

Note: The last line must have 0 spaces in it. 


Solution :


                            Solution in C :

In C :

void staircase(int n) {
    for(int i=0;i<n;i++)
        for(int j=0;j<n-i-1;j++)
            printf(" ");

        for(int k = i; k >= 0; k--)



#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {

    int n;
    cin >> n;
    string str(n, ' ');
    for (int i = 1; i <= n; ++i) {
        str[n-i] = '#';
        cout << str << endl;
    return 0;

In Python3 :

m=" "
while n>n-n:

In Java :

import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

	public static void main(String[] args) {

		Scanner sc = new Scanner(;
		int N = sc.nextInt();
		for(int i=1;i<=N;i++) {
			for(int j=1;j<=N-i;j++){
				System.out.print(" ");
			for(int k=0;k<i;k++)


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