**Max Product of Three Numbers - Amazon Top Interview Questions**

### Problem Statement :

Given a list of integers nums, find the largest product of three distinct elements. Constraints 3 ≤ n ≤ 100,000 where n is the length of nums Example 1 Input nums = [5, 4, 1, 3, -2, -2] Output 60 Explanation We can multiply 5 * 4 * 3 Example 2 Input nums = [-3, 1, 1, 0] Output 0 Explanation We can multiply 1 * 1 * 0

### Solution :

` ````
Solution in C++ :
int solve(vector<int>& nums) {
sort(begin(nums), end(nums));
int ans = max(nums[0] * nums[1] * nums[nums.size() - 1],
nums[nums.size() - 1] * nums[nums.size() - 2] * nums[nums.size() - 3]);
return ans;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public int solve(int[] nums) {
int max1 = Integer.MIN_VALUE, max2 = max1, max3 = max1;
int min1 = Integer.MAX_VALUE, min2 = min1;
for (int num : nums) {
// Find 3 max nums
if (num > max1) {
max3 = max2;
max2 = max1;
max1 = num;
} else if (num > max2) {
max3 = max2;
max2 = num;
} else if (num > max3)
max3 = num;
// Find 2 min nums
if (num < min1) {
min2 = min1;
min1 = num;
} else if (num < min2)
min2 = num;
}
return Math.max(max1 * max2 * max3, max1 * min1 * min2);
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, l):
l = sorted(l)
return max(l[-1] * l[-2] * l[-3], l[0] * l[1] * l[-1])
```

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