# Dynamic Array in C

### Problem Statement :

```Snow Howler is the librarian at the central library of the city of HuskyLand. He must handle requests which come in the following forms:

1 x y : Insert a book with y pages at the end of the xth  shelf.

2 x y : Print the number of pages in the yth
book on the xth shelf.

3 x : Print the number of books on the xth shelf.

Snow Howler has got an assistant, Oshie, provided by the Department of Education. Although inexperienced, Oshie can handle all of the queries of types 2 and 3.

Help Snow Howler deal with all the queries of type 1.

Oshie has used two arrays:

int* total_number_of_books;
/*
* This stores the total number of books on each shelf.
*/

int** total_number_of_pages;
/*
* This stores the total number of pages in each book of each shelf.
* The rows represent the shelves and the columns represent the books.
*/

Input Format

The first line contains an integer  total_number_of_shelves , the number of shelves in the library.
The second line contains an integer total_number_of_queries , the number of requests.
Each of the following  total_number_of_queries lines contains a request in one of the three specified formats.

Constraints

1 <=    total_number_of_shelves  <= 10^5
1 <=    total_number_of_queries    <= 10^5
For each query of the second type, it is guaranteed that a book is present on the xth shelf at yth index.
0  <= x <  total_number_of_shelves
Both the shelves and the books are numbered starting from 0.
Maximum number of books per shelf <= 1100.

Output Format

Write the logic for the requests of type 1. The logic for requests of types 2 and 3 are provided.```

### Solution :

```                            ```Solution in C :

int main()
{
int total_number_of_shelves;
scanf("%d", &total_number_of_shelves);

int total_number_of_queries;
scanf("%d", &total_number_of_queries);

total_number_of_books=(int*)malloc(sizeof(int)*total_number_of_shelves);

total_number_of_pages=(int**)malloc(sizeof(int*)*total_number_of_shelves);

for(int i=0; i<total_number_of_shelves; i++){
total_number_of_books[i]=0;
total_number_of_pages[i]=(int*)malloc(sizeof(int));
}

while (total_number_of_queries--) {
int type_of_query;
scanf("%d", &type_of_query);

if (type_of_query == 1) {
int x, y;
scanf("%d %d", &x, &y);
*(total_number_of_books+x)+=1;
*(total_number_of_pages+x)=realloc(*(total_number_of_pages+x), *(total_number_of_books+x)*sizeof(int));
*(*(total_number_of_pages+x)+*(total_number_of_books+x)-1)=y;```
```

## Left Rotation

A left rotation operation on an array of size n shifts each of the array's elements 1 unit to the left. Given an integer, d, rotate the array that many steps left and return the result. Example: d=2 arr=[1,2,3,4,5] After 2 rotations, arr'=[3,4,5,1,2]. Function Description: Complete the rotateLeft function in the editor below. rotateLeft has the following parameters: 1. int d

## Sparse Arrays

There is a collection of input strings and a collection of query strings. For each query string, determine how many times it occurs in the list of input strings. Return an array of the results. Example: strings=['ab', 'ab', 'abc'] queries=['ab', 'abc', 'bc'] There are instances of 'ab', 1 of 'abc' and 0 of 'bc'. For each query, add an element to the return array, results=[2,1,0]. Fun

## Array Manipulation

Starting with a 1-indexed array of zeros and a list of operations, for each operation add a value to each of the array element between two given indices, inclusive. Once all operations have been performed, return the maximum value in the array. Example: n=10 queries=[[1,5,3], [4,8,7], [6,9,1]] Queries are interpreted as follows: a b k 1 5 3 4 8 7 6 9 1 Add the valu

## Print the Elements of a Linked List

This is an to practice traversing a linked list. Given a pointer to the head node of a linked list, print each node's data element, one per line. If the head pointer is null (indicating the list is empty), there is nothing to print. Function Description: Complete the printLinkedList function in the editor below. printLinkedList has the following parameter(s): 1.SinglyLinkedListNode

## Insert a Node at the Tail of a Linked List

You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Input Format: You have to complete the SinglyLink