# Anagram Substrings - Amazon Top Interview Questions

### Problem Statement :

```Given two strings s0 and s1, return the number of substrings where s1 contains any anagram of s0.

Constraints

n ≤ 100,000 where n is the length of s0
m ≤ 100,000 where m is the length of s1

Example 1

Input

s0 = "abc"
s1 = "bcabxabc"

Output

3

Explanation

The substrings "bca", "cab" and "abc" of s0 are permutations of "abc".```

### Solution :

```                        ```Solution in C++ :

int solve(string s0, string s1) {
if (s0.size() > s1.size()) return 0;
vector<int> v0(26), v1(26);
int n = s0.size(), ans = 0;
for (char c : s0) v0[c - 'a']++;
for (int i = 0; i < n; i++) v1[s1[i] - 'a']++;
ans += v0 == v1;
for (int i = n; i < s1.size(); i++) {
v1[s1[i] - 'a']++;
v1[s1[i - n] - 'a']--;
ans += v0 == v1;
}
return ans;
}```
```

```                        ```Solution in Python :

class Solution:
def solve(self, s0, s1):

charset = Counter(s0)
k, n, count = len(s0), len(s1), 0

ct = Counter(s1[:k])
for i in range(0, len(s1) - k + 1):

if ct & charset == charset:
count += 1

ct[s1[i]] -= 1

if i + k < n:
ct[s1[i + k]] += 1
return count```
```

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