**Anagram Substrings - Amazon Top Interview Questions**

### Problem Statement :

Given two strings s0 and s1, return the number of substrings where s1 contains any anagram of s0. Constraints n ≤ 100,000 where n is the length of s0 m ≤ 100,000 where m is the length of s1 Example 1 Input s0 = "abc" s1 = "bcabxabc" Output 3 Explanation The substrings "bca", "cab" and "abc" of s0 are permutations of "abc".

### Solution :

` ````
Solution in C++ :
int solve(string s0, string s1) {
if (s0.size() > s1.size()) return 0;
vector<int> v0(26), v1(26);
int n = s0.size(), ans = 0;
for (char c : s0) v0[c - 'a']++;
for (int i = 0; i < n; i++) v1[s1[i] - 'a']++;
ans += v0 == v1;
for (int i = n; i < s1.size(); i++) {
v1[s1[i] - 'a']++;
v1[s1[i - n] - 'a']--;
ans += v0 == v1;
}
return ans;
}
```

` ````
Solution in Python :
class Solution:
def solve(self, s0, s1):
charset = Counter(s0)
k, n, count = len(s0), len(s1), 0
ct = Counter(s1[:k])
for i in range(0, len(s1) - k + 1):
if ct & charset == charset:
count += 1
ct[s1[i]] -= 1
if i + k < n:
ct[s1[i + k]] += 1
return count
```

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