XOR Strings


Problem Statement :


In this challenge, the task is to debug the existing code to successfully execute all provided test files.

Given two strings consisting of digits 0 and 1 only, find the XOR of the two strings.

To know more about XOR Click Here

Debug the given function strings_xor to find the XOR of the two given strings appropriately.

Note: You can modify at most three lines in the given code and you cannot add or remove lines to the code.

To restore the original code, click on the icon to the right of the language selector.

Input Format

The input consists of two lines. The first line of the input contains the first string, s, and the second line contains the second string, t.


Constraints

1  <=   | s |  <=  10^4
| s |  =  | t |

Output Format

Print the string obtained by the XOR of the two input strings in a single line.


Solution :



title-img 


                            Solution in C :

In  C++  :






#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

string strings_xor(string s, string t) {
    
    string res = "";
    for(int i = 0; i < s.size(); i++) {
        if(s[i] == t[i])
            res += '0';
        else
            res += '1';
    }
    
    return res;
}

int main() {
    string s, t;
    cin >> s >> t;
    cout << strings_xor(s, t) << endl;
    return 0;
}








In    Java  :







import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {
    
    public static String stringsXOR(String s, String t) {
        String res = new String("");
        for(int i = 0; i < s.length(); i++) {
            if(s.charAt(i)== t.charAt(i))
                res = res+"0";
            else
                res =res+ "1";
        }
        
        return res;
    }
    
    public static void main(String[] args) {
    
        String s, t;
        Scanner in = new Scanner(System.in);
        s = in.nextLine();
        t = in.nextLine();
        System.out.println(stringsXOR(s, t));
        
    }
    
}








In    Python3 





def strings_xor(s, t):
    res = ""
    for i in range(len(s)):
        if s[i] == t[i]:
            res += '0'
        else:
            res += '1'
            
    return res
  
s = input()
t = input()
print(strings_xor(s, t))








View More Similar Problems

Print in Reverse

Given a pointer to the head of a singly-linked list, print each data value from the reversed list. If the given list is empty, do not print anything. Example head* refers to the linked list with data values 1->2->3->Null Print the following: 3 2 1 Function Description: Complete the reversePrint function in the editor below. reversePrint has the following parameters: Sing

View Solution →

Reverse a linked list

Given the pointer to the head node of a linked list, change the next pointers of the nodes so that their order is reversed. The head pointer given may be null meaning that the initial list is empty. Example: head references the list 1->2->3->Null. Manipulate the next pointers of each node in place and return head, now referencing the head of the list 3->2->1->Null. Function Descriptio

View Solution →

Compare two linked lists

You’re given the pointer to the head nodes of two linked lists. Compare the data in the nodes of the linked lists to check if they are equal. If all data attributes are equal and the lists are the same length, return 1. Otherwise, return 0. Example: list1=1->2->3->Null list2=1->2->3->4->Null The two lists have equal data attributes for the first 3 nodes. list2 is longer, though, so the lis

View Solution →

Merge two sorted linked lists

This challenge is part of a tutorial track by MyCodeSchool Given pointers to the heads of two sorted linked lists, merge them into a single, sorted linked list. Either head pointer may be null meaning that the corresponding list is empty. Example headA refers to 1 -> 3 -> 7 -> NULL headB refers to 1 -> 2 -> NULL The new list is 1 -> 1 -> 2 -> 3 -> 7 -> NULL. Function Description C

View Solution →

Get Node Value

This challenge is part of a tutorial track by MyCodeSchool Given a pointer to the head of a linked list and a specific position, determine the data value at that position. Count backwards from the tail node. The tail is at postion 0, its parent is at 1 and so on. Example head refers to 3 -> 2 -> 1 -> 0 -> NULL positionFromTail = 2 Each of the data values matches its distance from the t

View Solution →

Delete duplicate-value nodes from a sorted linked list

This challenge is part of a tutorial track by MyCodeSchool You are given the pointer to the head node of a sorted linked list, where the data in the nodes is in ascending order. Delete nodes and return a sorted list with each distinct value in the original list. The given head pointer may be null indicating that the list is empty. Example head refers to the first node in the list 1 -> 2 -

View Solution →