# Weighted Uniform Strings

### Problem Statement :

```A weighted string is a string of lowercase English letters where each letter has a weight. Character weights are 1 to 26  from  a to z  as shown below:

The weight of a string is the sum of the weights of its characters. For example:

A uniform string consists of a single character repeated zero or more times. For example, ccc and a are uniform strings, but bcb and cd are not.

Function Description

Complete the weightedUniformStrings function in the editor below.

weightedUniformStrings has the following parameter(s):
- string s: a string
- int queries[n]: an array of integers

Returns
- string[n]: an array of strings that answer the queries

Input Format

The first line contains a string s, the original string.
The second line contains an integer n, the number of queries.
Each of the next s lines contains an integer queries[i], the weight of a uniform subtring of s that may or may not exist.

Constraints

1  <=  length of s,n  <=  10^5
1  <=   queries[i]  <=  10^7
s will only contain lowercase English letters, ascii[a-z].```

### Solution :

```                            ```Solution in C :

In   C++  :

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;

bool reach[10000010];

int main(){
string s;
cin >> s;

int val = 0;
for (int i=0; i<s.size(); i++) {
if (i > 0 && s[i] != s[i-1]) val = 0;
val += (s[i]-'a'+1);
reach[val] = true;
}

int n;
cin >> n;
for(int a0 = 0; a0 < n; a0++){
int x;
cin >> x;
cout << (reach[x] ? "Yes\n" : "No\n");
}
return 0;
}

In  Java  :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String s = in.next();
int len =  s.length();
int n = in.nextInt();
Set<Integer> set = new HashSet<Integer>();
int i=0;
while(i<len){
int j=i;
int sum =0;
while( j<len && s.charAt(i)==s.charAt(j) ){
sum += (s.charAt(i)-'a') +1;
j++;
}
i = j;
}
for(int a0 = 0; a0 < n; a0++){
int x = in.nextInt();
if (set.contains(x)){
System.out.println("Yes");
}
else{
System.out.println("No");
}
}
}
}

In   C :

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
char* s = (char *)malloc(512000 * sizeof(char));
scanf("%s",s);
int n;
scanf("%d",&n);
int *cnt = (int*)malloc(32 * sizeof(int));
for(int i=0;i<26;i++)cnt[i]=0;
int len = strlen(s);
int bef = 27, cont = 0;
for(int i=0;i<len;i++){
int id = s[i]-'a';
if(id!=bef){
bef=id;
cont=0;
}
cont++;
cnt[id]=fmax(cnt[id],cont);
}
for(int a0 = 0; a0 < n; a0++){
int x;
scanf("%d",&x);
bool ok = false;
for(int c=0;c<26;c++){
int w = c+1;
if(x%w)continue;
if(x/w > cnt[c])continue;
ok=true;
break;
}
puts(ok?"Yes":"No");
}
return 0;
}

In   Python3 :

s = input().strip()
cost = set()
prev = ''
count = 0
for i in s:
if i != prev:
prev = i
count = 0
count += 1
cost.add(count * (ord(i) - ord('a') + 1))
for _ in range(int(input())):
print("Yes" if int(input()) in cost else "No")```
```

## Array Manipulation

Starting with a 1-indexed array of zeros and a list of operations, for each operation add a value to each of the array element between two given indices, inclusive. Once all operations have been performed, return the maximum value in the array. Example: n=10 queries=[[1,5,3], [4,8,7], [6,9,1]] Queries are interpreted as follows: a b k 1 5 3 4 8 7 6 9 1 Add the valu

## Print the Elements of a Linked List

This is an to practice traversing a linked list. Given a pointer to the head node of a linked list, print each node's data element, one per line. If the head pointer is null (indicating the list is empty), there is nothing to print. Function Description: Complete the printLinkedList function in the editor below. printLinkedList has the following parameter(s): 1.SinglyLinkedListNode

## Insert a Node at the Tail of a Linked List

You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Input Format: You have to complete the SinglyLink