Sum of Digits of a Five Digit Number


Problem Statement :


Objective:

The modulo operator, %, returns the remainder of a division. For example, 4 % 3 = 1 and 12 % 10 = 2. The ordinary division operator, /, returns a truncated integer value when performed on integers. For example, 5 / 3 = 1. To get the last digit of a number in base 10, use 10 as the modulo divisor.


Task:

Given a five digit integer, print the sum of its digits.


Input Format:

The input contains a single five digit number, .


Constraints:
10000<=n<=99999


Output Format:

Print the sum of the digits of the five digit number.



Solution :



title-img


                            Solution in C :

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
	
   int n;
   scanf("%d", &n);
   int digit, temp, sum = 0;
   temp = n;
 
   while(temp > 0)
   {
     digit = temp % 10;
     sum = sum + digit;
     temp = temp / 10;
   }
   
   printf("%d\n",sum);
   return 0;
}
                        








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