**Sum of Digits of a Five Digit Number**

### Problem Statement :

Objective: The modulo operator, %, returns the remainder of a division. For example, 4 % 3 = 1 and 12 % 10 = 2. The ordinary division operator, /, returns a truncated integer value when performed on integers. For example, 5 / 3 = 1. To get the last digit of a number in base 10, use 10 as the modulo divisor. Task: Given a five digit integer, print the sum of its digits. Input Format: The input contains a single five digit number, . Constraints: 10000<=n<=99999 Output Format: Print the sum of the digits of the five digit number.

### Solution :

` ````
Solution in C :
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
int n;
scanf("%d", &n);
int digit, temp, sum = 0;
temp = n;
while(temp > 0)
{
digit = temp % 10;
sum = sum + digit;
temp = temp / 10;
}
printf("%d\n",sum);
return 0;
}
```

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