Stuck Keyboard- Google Top Interview Questions

Problem Statement :

```You are given two strings typed and target.
You want to write target, but the keyboard is stuck so some characters may be written 1 or more times. Return whether it's possible that typed was meant to write target.

Constraints

n ≤ 100,000 where n is the length of typed

m ≤ 100,000 where n is the length of s

Example 1

Input

typed = "aaabcccc"

target = "abc"

Output

True

Explanation

Each of the "a", "b", and "c" were typed

Example 2

Input

typed = "abc"

target = "ab"

Output

False

Explanation

"c" was not typed```

Solution :

```                        ```Solution in C++ :

bool solve(string s, string t) {
int curr = 0;
for (int i = 0; i < t.size();) {
int j = i + 1;
while (j < t.size() && t[j] == t[i]) j++;
if (curr == s.size()) return false;
if (s[curr] != t[i]) return false;
int nextindex = curr;
while (nextindex < s.size() && s[nextindex] == s[curr]) nextindex++;
if (nextindex - curr < j - i) return false;
curr = nextindex;
i = j;
}
return curr == s.size();
}```
```

```                        ```Solution in Java :

import java.util.*;

class Solution {
public boolean solve(String s, String t) {
int k = 0;

for (int i = 0; i < s.length(); i++) {
if (k >= t.length() || s.charAt(i) != t.charAt(k)) {
return false;
}

int j = i;
int cnt1 = 0;
int cnt2 = 0;

while (j < s.length() && s.charAt(j) == s.charAt(i)) {
j++;
cnt1++;
}
i = j - 1;

j = k;
while (j < t.length() && t.charAt(j) == t.charAt(k)) {
j++;
cnt2++;
}
k = j;

if (cnt1 < cnt2)
return false;
}

if (k != t.length())
return false;
return true;
}
}```
```

```                        ```Solution in Python :

from itertools import groupby, zip_longest

class Solution:
def solve(self, typed, target):
return all(
x is not None and y is not None and x[0] == y[0] and len(list(x[1])) <= len(list(y[1]))
for (x, y) in zip_longest(groupby(target), groupby(typed))
)```
```

Tree: Preorder Traversal

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Tree: Postorder Traversal

Complete the postorder function in the editor below. It received 1 parameter: a pointer to the root of a binary tree. It must print the values in the tree's postorder traversal as a single line of space-separated values. Input Format Our test code passes the root node of a binary tree to the postorder function. Constraints 1 <= Nodes in the tree <= 500 Output Format Print the

Tree: Inorder Traversal

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Tree: Height of a Binary Tree

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Tree : Top View

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Tree: Level Order Traversal

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