**Solve Me First**

### Problem Statement :

Complete the function solveMeFirst to compute the sum of two integers. Function prototype: int solveMeFirst(int a, int b); where, a is the first integer input. b is the second integer input Return values sum of the above two integers

### Solution :

` ````
Solution in C :
In C :
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int solveMeFirst(int a, int b) {
int result = a + b ;
return result;
}
int main() {
int num1,num2;
scanf("%d %d",&num1,&num2);
int sum;
sum = solveMeFirst(num1,num2);
printf("%d",sum);
return 0;
}
In C++:
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int solveMeFirst(int a, int b) {
return a+b;
}
int main() {
int num1, num2;
int sum;
cin>>num1>>num2;
sum = solveMeFirst(num1,num2);
cout<<sum;
return 0;
}
In Java:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
static int solveMeFirst(int a, int b) {
return a+b;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int _a;
_a = in.nextInt();
int _b;
_b = in.nextInt();
int sum;
sum = solveMeFirst(_a, _b);
System.out.println(sum);
}
}
In Python3:
def solveMeFirst(a,b):
return a+b
num1 = int(input())
num2 = int(input())
res = solveMeFirst(num1,num2)
print (res)
```

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