Sam's Puzzle (Approximate)
Problem Statement :
Sam invented a new puzzle game played on an n x n matrix named puzzle, where each cell contains a unique integer in the inclusive range between 1 and n^2. The coordinate of the top-left cell is (1, 1). The Moves A move consists of two steps: Choose a sub-square of puzzle. Rotate the sub-square in the clockwise direction. Good Pairs of Cells A pair of cell is good if one of the following is true: They're located in the same row and the number in the left cell is less than the number in the right cell. They're located in the same column and the number in the upper cell is less than the number in the lower cell. The diagram below depicts all the good pairs of cells located in the same row: Goodness of a Square We define the goodness of a sub-square to be the total number of good pairs of cells in the sub-square. The Goal Given the initial value of puzzle, maximize its goodness as much as is possible by performing a sequence of at most 500 moves. Then print the necessary moves according to the Output Format specified below. Input Format The first line contains an integer denoting n. Each of the n subsequent lines contains n space-separated integers. The jth integer in the ith line denotes the cell located in coordinate (i, j ) Constraints 1 <= n <= 30 Each cell contains a unique number in the inclusive range between 1 and n^2. Output Format Print the following lines of output: On the first line, print an integer, m, denoting the number of moves necessary to maximize the goodness of puzzle. Recall that this number must be <= 500 . For each move, print three space-separated integers describing its respective ,i , j and k values on a new line. Recall that a move is described as the clockwise rotation of a k x k sub-square whose top-left corner is located at coordinate ( i, j ).
Solution :
Solution in C :
In Python3 :
#!/bin/python3
import math
import os
import random
import re
import sys
import itertools
import time
def score(a):
count = 0
for r in range(len(a)):
for ind in itertools.combinations(range(len(a)), 2):
if a[r][ind[0]] < a[r][ind[1]]:
count += 1
for c in range(len(a[0])):
for ind in itertools.combinations(range(len(a[0])), 2):
if a[ind[0]][c] < a[ind[1]][c]:
count += 1
return count
def rotate(a, r, c, d):
seg = [[a[i][c+j] for i in range(r+d, r-1, -1)] for j in range(d+1)]
for i in range(d+1):
for j in range(d+1):
a[r+i][c+j] = seg[i][j]
def undo(a, r, c, d):
seg = [[a[r+i][j] for i in range(d+1)] for j in range(c+d, c-1, -1)]
for i in range(d+1):
for j in range(d+1):
a[r+i][c+j] = seg[i][j]
def getRandom():
r = random.randint(0, len(a)-2)
c = random.randint(0, len(a)-2)
d = random.randint(1, len(a)-1-max(r,c))
return r, c, d
def countDes(a):
arrayMax = []
for i in range(len(a[0])-1):
count = 1
curI = 0
curMax = 1
posMax = 0
for j in range(1, len(a)):
if a[j][i] < a[j-1][i]:
count+= 1
if j == len(a) - 1:
if count > curMax:
curMax = count
posMax = curI
else:
if count > curMax:
curMax = count
posMax = curI
count = 1
curI = j
# length #r #c
arrayMax.append([curMax, posMax, i])
return arrayMax
def processNotRandom(a, getArray, history):
maxPos = -1
maxScore = score(a)
for i in range(len(getArray)):
r = getArray[i][1]
c = getArray[i][2]
d = min(len(a)-1-max(r,c), getArray[i][0])
rotate(a, r, c, d)
sc = score(a)
if sc > maxScore:
maxPos = i
maxScore = sc
undo(a, r, c, d)
if maxPos != -1:
r = getArray[maxPos][1]
c = getArray[maxPos][2]
d = min(len(a)-1-max(r,c), getArray[maxPos][0])
rotate(a, r, c, d)
history.append([r+1, c+1, d+1])
n = int(input())
a = []
for _ in range(n):
a.append(list(map(int, input().rstrip().split())))
# Write Your Code Here
curMax = score(a)
curSc = curMax
start = time.time()
Beta = 0.8
Beta_increase = 0.8
history = []
maxScore = score(a)
maxPos = -1
i = 0
while time.time() - start < 8.0 and len(history) < 500:
r, c, d = getRandom()
numRotate = 0
for j in range(3):
rotate(a, r, c, d)
sc = score(a)
if sc > maxScore:
maxScore = sc
numRotate = j + 1
rotate(a, r, c, d)
for j in range(numRotate):
history.append([r+1, c+1, d+1])
rotate(a, r, c, d)
print(len(history))
for i in range(0, len(history)):
print('{} {} {}'.format(history[i][0], history[i][1], history[i][2]))
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