# Repeating String - Amazon Top Interview Questions

### Problem Statement :

```Given a lowercase alphabet string s, return whether it's a repeating string.

Constraints

n ≤ 100,000 where n is the length of s

Example 1

Input

s = "dogdogdog"

Output
True

Explanation
"dog" is repeated.

Example 2

Input
s = "catdog"

Output
False```

### Solution :

```                        ```Solution in C++ :

bool solve(string s) {
const size_t size_2 = s.size() >> 1;
for (size_t pattern_size = s.find(s[0], 1); pattern_size <= size_2;
pattern_size = s.find(s[0], pattern_size + 1)) {
const size_t N = s.size() / pattern_size;
if (N * pattern_size == s.size()) {
if (N & 1) {
const size_t ssize = s.size() - pattern_size;
const size_t half = ssize >> 1;
if (memcmp(&s[0], &s[ssize], pattern_size) == 0 &&
memcmp(&s[0], &s[half], half) == 0)
return true;
} else {
if (memcmp(&s[0], &s[size_2], size_2) == 0) return true;
}
}
}
return false;
}```
```

```                        ```Solution in Java :

import java.util.*;

class Solution {
public boolean solve(String s) {
return ((s + s).indexOf(s, 1) != s.length());
}
}```
```

```                        ```Solution in Python :

class Solution:
def solve(self, s):
if len(s) == 1:
return False

for i in range(1, len(s) // 2 + 1):
if len(s) % i == 0:
reciprocal = len(s) // i
if s == s[:i] * reciprocal:
return True

return False```
```

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