Number of Moves to Capture the King - Google Top Interview Questions


Problem Statement :


You are given a two-dimensional integer matrix board containing 0s, 1s and 2s representing some n x n chessboard. 

Each 0 represents an empty cell, 1 represents the knight and 2 represents the king. 

There is at least one knight but exactly one king.

Given that the king stays still, return the minimum number of moves it would take for some knight to land on the king. 

If there's no solution, return -1. A knight can't land on another knight.

Constraints

2 ≤ n ≤ 500 where n is the number of rows and columns in board

1 ≤ t < n * n where t is the number of knights

k = 1 where k is the number of kings.

Example 1

Input

board = [

    [1, 0, 0, 0, 0],

    [0, 0, 0, 0, 0],

    [0, 0, 0, 0, 2],

    [1, 0, 0, 0, 0],

    [0, 0, 0, 0, 0]

]

Output

2

Explanation

The knight on top left corner can jump twice to land on the king.



Example 2

Input

board = [

    [1, 2],

    [1, 1]

]

Output

-1

Explanation

There is no way to land on the king here.



Solution :



title-img




                        Solution in C++ :

int solve(vector<vector<int>>& nums) {
    int n = nums.size(), m = nums[0].size();
    vector<vector<int>> dist(n, vector<int>(m, INT_MAX));
    queue<pair<int, int>> q;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            if (nums[i][j] == 2) {
                dist[i][j] = 0;
                q.push({i, j});
                break;
            }
        }
    }
    if (q.empty()) return -1;

    vector<int> xdir{1, 2, -1, 2, -1, -2, 1, -2};
    vector<int> ydir{2, 1, 2, -1, -2, -1, -2, 1};
    while (!q.empty()) {
        auto [i, j] = q.front();
        q.pop();
        for (int k = 0; k < 8; k++) {
            int x = i + xdir[k];
            int y = j + ydir[k];
            if (x >= 0 and x < n and y >= 0 and y < m and nums[x][y] != 2 and
                dist[x][y] > dist[i][j] + 1) {
                if (nums[x][y] == 1) return dist[i][j] + 1;
                dist[x][y] = dist[i][j] + 1;
                q.push({x, y});
            }
        }
    }
    return -1;
}
                    


                        Solution in Java :

import java.util.*;

class Solution {
    int[] dr = {-1, -1, 1, 1, 2, 2, -2, -2};
    int[] dc = {2, -2, 2, -2, 1, -1, 1, -1};

    public int solve(int[][] board) {
        LinkedList<Pair<Integer, Integer>> q = new LinkedList();
        HashSet<Pair<Integer, Integer>> hs = new HashSet();
        int m = board.length, n = board[0].length;
        int king_r = 0, king_c = 0;

        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n; j++) {
                if (board[i][j] == 1) {
                    q.addLast(new Pair(i, j));
                    hs.add(new Pair(i, j));
                } else if (board[i][j] == 2) {
                    king_r = i;
                    king_c = j;
                }
            }
        }
        int moves = 0;
        while (q.size() > 0) {
            int size = q.size();
            for (int i = 0; i < size; i++) {
                Pair<Integer, Integer> cur = q.removeFirst();
                int cur_r = cur.getKey(), cur_c = cur.getValue();
                if (cur_r == king_r && cur_c == king_c)
                    return moves;
                for (int move = 0; move < 8; move++) {
                    int new_r = cur_r + dr[move];
                    int new_c = cur_c + dc[move];
                    if (new_r < 0 || new_c < 0 || new_c >= n || new_r >= m)
                        continue;
                    if (hs.contains(new Pair(new_r, new_c)))
                        continue;
                    hs.add(new Pair(new_r, new_c));
                    q.addLast(new Pair(new_r, new_c));
                }
            }
            moves++;
        }
        return -1;
    }
}
                    


                        Solution in Python : 
                            
class Solution:
    def solve(self, board):
        r = len(board)
        c = len(board[0])
        dist = []
        for _ in range(r):
            dist.append([r * c + 1] * c)
        q = []
        sx, sy = None, None
        for i in range(r):
            for j in range(c):
                if board[i][j] == 1:
                    q.append((i, j))
                    dist[i][j] = 0
                elif board[i][j] == 2:
                    sx, sy = i, j
        for x, y in q:
            for dx, dy in [(-2, -1), (-2, 1), (-1, 2), (-1, -2), (1, -2), (1, 2), (2, -1), (2, 1)]:
                nx, ny = x + dx, y + dy
                if 0 <= nx < r and 0 <= ny < c and dist[nx][ny] > 1 + dist[x][y]:
                    dist[nx][ny] = 1 + dist[x][y]
                    q.append((nx, ny))
        ans = dist[sx][sy]
        if ans > r * c:
            ans = -1
        return ans
                    


View More Similar Problems

Self-Driving Bus

Treeland is a country with n cities and n - 1 roads. There is exactly one path between any two cities. The ruler of Treeland wants to implement a self-driving bus system and asks tree-loving Alex to plan the bus routes. Alex decides that each route must contain a subset of connected cities; a subset of cities is connected if the following two conditions are true: There is a path between ever

View Solution →

Unique Colors

You are given an unrooted tree of n nodes numbered from 1 to n . Each node i has a color, ci. Let d( i , j ) be the number of different colors in the path between node i and node j. For each node i, calculate the value of sum, defined as follows: Your task is to print the value of sumi for each node 1 <= i <= n. Input Format The first line contains a single integer, n, denoti

View Solution →

Fibonacci Numbers Tree

Shashank loves trees and math. He has a rooted tree, T , consisting of N nodes uniquely labeled with integers in the inclusive range [1 , N ]. The node labeled as 1 is the root node of tree , and each node in is associated with some positive integer value (all values are initially ). Let's define Fk as the Kth Fibonacci number. Shashank wants to perform 22 types of operations over his tree, T

View Solution →

Pair Sums

Given an array, we define its value to be the value obtained by following these instructions: Write down all pairs of numbers from this array. Compute the product of each pair. Find the sum of all the products. For example, for a given array, for a given array [7,2 ,-1 ,2 ] Note that ( 7 , 2 ) is listed twice, one for each occurrence of 2. Given an array of integers, find the largest v

View Solution →

Lazy White Falcon

White Falcon just solved the data structure problem below using heavy-light decomposition. Can you help her find a new solution that doesn't require implementing any fancy techniques? There are 2 types of query operations that can be performed on a tree: 1 u x: Assign x as the value of node u. 2 u v: Print the sum of the node values in the unique path from node u to node v. Given a tree wi

View Solution →

Ticket to Ride

Simon received the board game Ticket to Ride as a birthday present. After playing it with his friends, he decides to come up with a strategy for the game. There are n cities on the map and n - 1 road plans. Each road plan consists of the following: Two cities which can be directly connected by a road. The length of the proposed road. The entire road plan is designed in such a way that if o

View Solution →