**Longest Consecutive Duplicate String - Amazon Top Interview Questions**

### Problem Statement :

Given a lowercase alphabet string s, return the length of the longest substring with same characters. Constraints 0 ≤ n ≤ 100,000 where n is the length of s Example 1 Input s = "abbbba" Output 4 Explanation The longest substring is "bbbb". Example 2 Input s = "aaabbb" Output 3

### Solution :

` ````
Solution in C++ :
int solve(string s) {
int max = 0;
char curr = 0;
int count = 0;
for (int i = 0; i < s.size(); i++) {
if (s[i] == curr) {
count++;
} else {
if (count > max) max = count;
curr = s[i];
count = 1;
}
}
return max > count ? max : count;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public int solve(String s) {
if (s.length() < 1) {
return 0;
}
int ans = 1, temp = 1;
for (int i = 1; i < s.length(); i++) {
if (s.charAt(i - 1) == s.charAt(i)) {
temp++;
} else {
ans = Math.max(temp, ans);
temp = 1;
}
}
ans = Math.max(temp, ans);
return ans;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, s):
if not s:
return 0
tot = 1
size = 1
for ix in range(1, len(s)):
if s[ix] == s[ix - 1]:
size += 1
else:
tot = max(tot, size)
size = 1
tot = max(tot, size)
return tot
```

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