**Largest Pair of Points - Google Top Interview Questions**

### Problem Statement :

You are given a strictly increasing list of integers nums and a list of integers values, both of the same length. Find a pair i ≤ j that maximizes values[i] + values[j] + nums[j] - nums[i] and return the value. Constraints 2 ≤ n ≤ 100,000 where n is the length of nums and values Example 1 Input nums = [0, 1, 6] values = [-5, 5, 4] Output 14 Explanation Here we can pick i = 1 and j = 2 to get 5 + 4 + 6 - 1 Example 2 Input nums = [0, 3, 6] values = [-5, 4, 8] Output 16 Explanation Here we can pick i = 2 and j = 2 to get 8 + 8 + 6 - 6

### Solution :

` ````
Solution in C++ :
int solve(vector<int>& nums, vector<int>& values) {
int jsum = INT_MIN, isum = INT_MIN;
for (int i = 0; i < nums.size(); i++) {
int sum = nums[i] + values[i];
jsum = max(jsum, sum);
sum = values[i] - nums[i];
isum = max(isum, sum);
}
return isum + jsum;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public int solve(int[] nums, int[] values) {
int N = nums.length;
int max = Integer.MIN_VALUE;
int ans = Integer.MIN_VALUE;
for (int j = 0; j < N; j++) {
max = Math.max(max, values[j] - nums[j]);
ans = Math.max(ans, nums[j] + values[j] + max);
}
return ans;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, nums, values):
ans = -1e18
best = -1e18
for num, value in zip(nums, values):
best = max(best, value - num)
ans = max(ans, num + value + best)
return ans
```

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