Interval Painting - Google Top Interview Questions


Problem Statement :


You are given a list of integers walks and an integer target. 

You are currently at position 0 in a one-dimensional line. 

Each integer abs(walks[i]) represents the number of steps taken. 

Positive value means you walked right while negative value means you walked left.

We define a "block" as an interval of length 1 that has been walked on.

 For example, if you walk right 2 times, then you walked on blocks [0, 1] and [1, 2] once each. 

If you walk left once, then you'd walk on block [1, 2] again.

Return the number of blocks that's been walked on at least target number of times.

Constraints

0 ≤ n ≤ 100,000 where n is the length of walks


1 ≤ target

Example 1

Input

walks = [2, -4, 1]

target = 2

Output

3

Explanation

graph



We move right 2 steps right and then 4 steps left and then 1 step right. So we step on blocks [-2, -1], [0, 
1] and [1, 2] 2 times.


Solution :



title-img 




                        Solution in C++ :

int solve(vector<int> &nums, int target) {
    map<int, int> m;
    int current = 0;
    for (auto n : nums) {
        int last = current + n;
        if (n >= 0) {
            m[current] += 1;
            m[last] -= 1;
        } else {
            m[last] += 1;
            m[current] -= 1;
        }
        current = last;
    }
    int prev = 0;
    for (auto &[x, y] : m) {
        y += prev;
        prev = y;
    }
    int s = -1e9, ans = 0;
    for (auto &[x, y] : m) {
        if (y >= target) {
            if (s == -1e9) s = x;
        } else {
            if (s != -1e9) {
                ans += (x - s);
                s = -1e9;
            }
        }
    }
    return ans;
}
                    


                        Solution in Java :

import java.util.*;

class Solution {
    public int solve(int[] nums, int target) {
        Map<Integer, Integer> map = new TreeMap<>();

        int curr = 0;
        for (int num : nums) {
            int left = curr, right = curr;

            if (num < 0)
                left += num;
            else
                right += num;

            map.put(left, map.getOrDefault(left, 0) + 1);
            map.put(right, map.getOrDefault(right, 0) - 1);

            curr += num;
        }

        int res = 0, prev = 0, walk = 0;
        for (int key : map.keySet()) {
            if (walk >= target)
                res += Math.abs(key - prev);
            walk += map.get(key);
            prev = key;
        }

        return res;
    }
}
                    


                        Solution in Python : 
                            
class Solution:
    def solve(self, nums, target):
        pos = 0
        jumps = defaultdict(int)
        for dist in nums:
            jumps[pos] += 1 if dist > 0 else -1
            jumps[pos + dist] -= 1 if dist > 0 else -1
            pos += dist
        lastpos = level = total = 0
        for pos, val in sorted(jumps.items()):
            if level >= target:
                total += pos - lastpos
            level += val
            lastpos = pos
        return total


View More Similar Problems

Equal Stacks

ou have three stacks of cylinders where each cylinder has the same diameter, but they may vary in height. You can change the height of a stack by removing and discarding its topmost cylinder any number of times. Find the maximum possible height of the stacks such that all of the stacks are exactly the same height. This means you must remove zero or more cylinders from the top of zero or more of

View Solution →

Game of Two Stacks

Alexa has two stacks of non-negative integers, stack A = [a0, a1, . . . , an-1 ] and stack B = [b0, b1, . . . , b m-1] where index 0 denotes the top of the stack. Alexa challenges Nick to play the following game: In each move, Nick can remove one integer from the top of either stack A or stack B. Nick keeps a running sum of the integers he removes from the two stacks. Nick is disqualified f

View Solution →

Largest Rectangle

Skyline Real Estate Developers is planning to demolish a number of old, unoccupied buildings and construct a shopping mall in their place. Your task is to find the largest solid area in which the mall can be constructed. There are a number of buildings in a certain two-dimensional landscape. Each building has a height, given by . If you join adjacent buildings, they will form a solid rectangle

View Solution →

Simple Text Editor

In this challenge, you must implement a simple text editor. Initially, your editor contains an empty string, S. You must perform Q operations of the following 4 types: 1. append(W) - Append W string to the end of S. 2 . delete( k ) - Delete the last k characters of S. 3 .print( k ) - Print the kth character of S. 4 . undo( ) - Undo the last (not previously undone) operation of type 1 or 2,

View Solution →

Poisonous Plants

There are a number of plants in a garden. Each of the plants has been treated with some amount of pesticide. After each day, if any plant has more pesticide than the plant on its left, being weaker than the left one, it dies. You are given the initial values of the pesticide in each of the plants. Determine the number of days after which no plant dies, i.e. the time after which there is no plan

View Solution →

AND xor OR

Given an array of distinct elements. Let and be the smallest and the next smallest element in the interval where . . where , are the bitwise operators , and respectively. Your task is to find the maximum possible value of . Input Format First line contains integer N. Second line contains N integers, representing elements of the array A[] . Output Format Print the value

View Solution →