FizzBuzz - Amazon Top Interview Questions


Problem Statement :


Given an integer n, return a list of integers from 1 to n as strings except for multiples of 3 use “Fizz” instead of the integer and for the multiples of 5 use “Buzz”. For integers which are multiples of both 3 and 5 use “FizzBuzz”.

Constraints

0 ≤ n ≤ 100,000

Example 1

Input

n = 15

Output

["1", "2", "Fizz", "4", "Buzz", "Fizz", "7", "8", "Fizz", "Buzz", "11", "Fizz", "13", "14", "FizzBuzz"]


Solution :



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                        Solution in C++ :

vector<string> solve(int n) {
    vector<string> res;
    for (int i = 1; i <= n; i++) {
        string s;
        if (i % 3 == 0) s += "Fizz";
        if (i % 5 == 0) s += "Buzz";

        res.push_back(s.empty() ? to_string(i) : s);
    }
    return res;
}
                    


                        Solution in Java :

import java.util.*;

class Solution {
    public String[] solve(int n) {
        String s[] = new String[n];
        s[0] = "1";
        for (int i = 1; i < s.length; i++) {
            if ((i + 1) % 3 == 0 && (i + 1) % 5 == 0) {
                s[i] = "FizzBuzz";
            } else if ((i + 1) % 3 == 0) {
                s[i] = "Fizz";
            } else if ((i + 1) % 5 == 0) {
                s[i] = "Buzz";
            } else {
                s[i] = String.valueOf(i + 1);
            }
        }
        return s;
    }
}
                    


                        Solution in Python : 
                            
class Solution:
    def solve(self, n):
        # return [self.convert_int(i) for i in range(1, n + 1)]
        return [
            "FizzBuzz" if not i % 15 else "Buzz" if not i % 5 else "Fizz" if not i % 3 else str(i)
            for i in range(1, n + 1)
        ]


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