# First to Count to Target- Google Top Interview Questions

### Problem Statement :

```You are playing a game against a friend where in each round you pick a number from 1 to k to add to a shared running total that initially starts from 0.
The first person to reach or exceed the running total to target wins.

Given that you go first, return whether you can force a win if everyone plays optimally.

Constraints

k ≤ 30

target ≤ 1,000

Example 1

Input

k = 5

target = 9

Output

True

Explanation

If we pick 3 first, then whether your friend picks 1, 2, ..., or 5 , we can always reach 9 by picking 5 next.

Example 2

Input

k = 3

target = 4

Output

False

Explanation

No mater what we pick your friend can pick 3 to reach 4.```

### Solution :

```                        ```Solution in C++ :

bool solve(int k, int target) {
return target % (k + 1);
}```
```

```                        ```Solution in Python :

class Solution:
def solve(self, k, target):
@functools.lru_cache(None)
def f(total):
win = False

if k + total >= target:
return True

for i in range(1, k + 1):
new_total = total + i
win = win or not f(new_total)

return win

return f(0)```
```

## Print in Reverse

Given a pointer to the head of a singly-linked list, print each data value from the reversed list. If the given list is empty, do not print anything. Example head* refers to the linked list with data values 1->2->3->Null Print the following: 3 2 1 Function Description: Complete the reversePrint function in the editor below. reversePrint has the following parameters: Sing

Given the pointer to the head node of a linked list, change the next pointers of the nodes so that their order is reversed. The head pointer given may be null meaning that the initial list is empty. Example: head references the list 1->2->3->Null. Manipulate the next pointers of each node in place and return head, now referencing the head of the list 3->2->1->Null. Function Descriptio

You’re given the pointer to the head nodes of two linked lists. Compare the data in the nodes of the linked lists to check if they are equal. If all data attributes are equal and the lists are the same length, return 1. Otherwise, return 0. Example: list1=1->2->3->Null list2=1->2->3->4->Null The two lists have equal data attributes for the first 3 nodes. list2 is longer, though, so the lis

## Merge two sorted linked lists

This challenge is part of a tutorial track by MyCodeSchool Given pointers to the heads of two sorted linked lists, merge them into a single, sorted linked list. Either head pointer may be null meaning that the corresponding list is empty. Example headA refers to 1 -> 3 -> 7 -> NULL headB refers to 1 -> 2 -> NULL The new list is 1 -> 1 -> 2 -> 3 -> 7 -> NULL. Function Description C

## Get Node Value

This challenge is part of a tutorial track by MyCodeSchool Given a pointer to the head of a linked list and a specific position, determine the data value at that position. Count backwards from the tail node. The tail is at postion 0, its parent is at 1 and so on. Example head refers to 3 -> 2 -> 1 -> 0 -> NULL positionFromTail = 2 Each of the data values matches its distance from the t

## Delete duplicate-value nodes from a sorted linked list

This challenge is part of a tutorial track by MyCodeSchool You are given the pointer to the head node of a sorted linked list, where the data in the nodes is in ascending order. Delete nodes and return a sorted list with each distinct value in the original list. The given head pointer may be null indicating that the list is empty. Example head refers to the first node in the list 1 -> 2 -