Count Substrings With All 1s - Google Top Interview Questions


Problem Statement :


You are given a string s containing "1"s and "0"s. 
Return the number of substrings that contain only "1"s. Mod the result by 10 ** 9 + 7.

Constraints

0 ≤ n ≤ 100,000 where n is the length of s

Example 1

Input

s = "111001"

Output

7

Explanation

Here are all the substrings containing only "1"s:



"1"

"1"

"1"

"1"

"11"

"11"

"111"



Solution :



title-img




                        Solution in C++ :

int solve(string s) {
    int i = 0, ans = 0, mod = 1e9 + 7;
    for (int j = 0; j < s.length(); j++) {
        if (s[j] == '0')
            i = j + 1;
        else
            ans = (ans + j - i + 1) % mod;
    }
    return ans;
}
                    


                        Solution in Java :

import java.util.*;

class Solution {
    public int solve(String s) {
        int tempResult = 0;
        int result = 0;
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == '1') {
                tempResult++;
            } else {
                while (tempResult > 0) {
                    result += tempResult;
                    tempResult--;
                }
            }
        }
        while (tempResult > 0) {
            result += tempResult;
            tempResult--;
        }

        return result;
    }
}
                    


                        Solution in Python : 
                            
class Solution:
    def solve(self, s):
        a = 0
        count = 0
        for i in range(len(s)):
            if s[i] == "0":
                a = 0
            else:
                a += 1
                count += a
        return count
                    


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