Count Substrings With All 1s - Google Top Interview Questions
Problem Statement :
You are given a string s containing "1"s and "0"s. Return the number of substrings that contain only "1"s. Mod the result by 10 ** 9 + 7. Constraints 0 ≤ n ≤ 100,000 where n is the length of s Example 1 Input s = "111001" Output 7 Explanation Here are all the substrings containing only "1"s: "1" "1" "1" "1" "11" "11" "111"
Solution :
Solution in C++ :
int solve(string s) {
int i = 0, ans = 0, mod = 1e9 + 7;
for (int j = 0; j < s.length(); j++) {
if (s[j] == '0')
i = j + 1;
else
ans = (ans + j - i + 1) % mod;
}
return ans;
}
Solution in Java :
import java.util.*;
class Solution {
public int solve(String s) {
int tempResult = 0;
int result = 0;
for (int i = 0; i < s.length(); i++) {
if (s.charAt(i) == '1') {
tempResult++;
} else {
while (tempResult > 0) {
result += tempResult;
tempResult--;
}
}
}
while (tempResult > 0) {
result += tempResult;
tempResult--;
}
return result;
}
}
Solution in Python :
class Solution:
def solve(self, s):
a = 0
count = 0
for i in range(len(s)):
if s[i] == "0":
a = 0
else:
a += 1
count += a
return count
View More Similar Problems
Tree: Preorder Traversal
Complete the preorder function in the editor below, which has 1 parameter: a pointer to the root of a binary tree. It must print the values in the tree's preorder traversal as a single line of space-separated values. Input Format Our test code passes the root node of a binary tree to the preOrder function. Constraints 1 <= Nodes in the tree <= 500 Output Format Print the tree's
View Solution →Tree: Postorder Traversal
Complete the postorder function in the editor below. It received 1 parameter: a pointer to the root of a binary tree. It must print the values in the tree's postorder traversal as a single line of space-separated values. Input Format Our test code passes the root node of a binary tree to the postorder function. Constraints 1 <= Nodes in the tree <= 500 Output Format Print the
View Solution →Tree: Inorder Traversal
In this challenge, you are required to implement inorder traversal of a tree. Complete the inorder function in your editor below, which has 1 parameter: a pointer to the root of a binary tree. It must print the values in the tree's inorder traversal as a single line of space-separated values. Input Format Our hidden tester code passes the root node of a binary tree to your $inOrder* func
View Solution →Tree: Height of a Binary Tree
The height of a binary tree is the number of edges between the tree's root and its furthest leaf. For example, the following binary tree is of height : image Function Description Complete the getHeight or height function in the editor. It must return the height of a binary tree as an integer. getHeight or height has the following parameter(s): root: a reference to the root of a binary
View Solution →Tree : Top View
Given a pointer to the root of a binary tree, print the top view of the binary tree. The tree as seen from the top the nodes, is called the top view of the tree. For example : 1 \ 2 \ 5 / \ 3 6 \ 4 Top View : 1 -> 2 -> 5 -> 6 Complete the function topView and print the resulting values on a single line separated by space.
View Solution →Tree: Level Order Traversal
Given a pointer to the root of a binary tree, you need to print the level order traversal of this tree. In level-order traversal, nodes are visited level by level from left to right. Complete the function levelOrder and print the values in a single line separated by a space. For example: 1 \ 2 \ 5 / \ 3 6 \ 4 F
View Solution →