Compare the Triplets
Problem Statement :
Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.
The rating for Alice's challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob's challenge is the triplet b = (b[0], b[1], b[2]).
The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].
If a[i] > b[i], then Alice is awarded 1 point.
If a[i] < b[i], then Bob is awarded 1 point.
If a[i] = b[i], then neither person receives a point.
Comparison points is the total points a person earned.
Given a and b, determine their respective comparison points.
Example
a = [1, 2, 3]
b = [3, 2, 1]
For elements *0*, Bob is awarded a point because a[0] .
For the equal elements a[1] and b[1], no points are earned.
Finally, for elements 2, a[2] > b[2] so Alice receives a point.
The return array is [1, 1] with Alice's score first and Bob's second.
Function Description
Complete the function compareTriplets in the editor below.
compareTriplets has the following parameter(s):
int a[3]: Alice's challenge rating
int b[3]: Bob's challenge rating
Return
int[2]: Alice's score is in the first position, and Bob's score is in the second.
Input Format
The first line contains 3 space-separated integers, a[0], a[1], and a[2], the respective values in triplet a.
The second line contains 3 space-separated integers, b[0], b[1], and b[2], the respective values in triplet b.
Constraints
1 ≤ a[i] ≤ 100
1 ≤ b[i] ≤ 100
Solution :
Solution in C :
In C++ :
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define mp make_pair
#define REP(i, n) for (int i = 0; i < (int)(n); ++i)
typedef long long LL;
typedef pair<int, int> PII;
int a[3], b[3];
int main() {
REP(i, 3) scanf("%d", a + i);
REP(i, 3) scanf("%d", b + i);
int x = 0, y = 0;
REP(i, 3) if (a[i] > b[i]) {
++x;
} else if (a[i] < b[i]) {
++y;
}
printf("%d %d\n", x, y);
return 0;
}
In C :
int* compareTriplets(int a_count, int* a, int b_count, int* b, int* result_count) {
int Alice_point = 0, Bob_point = 0;
for(int i = 0; i<a_count; i++)
{
if(a[i]==b[i])
{
}
if(a[i]>b[i])
{
Alice_point += 1;
}
if(a[i]<b[i])
{
Bob_point += 1;
}
}
*result_count = 2;
static int c[2];
c[0] = Alice_point;
c[1] = Bob_point;
return c;
}
In Java:
import java.io.*;
import java.util.*;
public class Solution {
private BufferedReader in;
private StringTokenizer line;
private PrintWriter out;
private static final int mm = 1000000007;
public void solve() throws IOException {
int[] a = nextIntArray(3);
int[] b = nextIntArray(3);
int aa = 0;
int bb = 0;
for (int i = 0; i < 3; i++) {
if (a[i] > b[i]) aa++;
else if (a[i] < b[i]) bb++;
}
out.println(aa + " " + bb);
}
public static void main(String[] args) throws IOException {
new Solution().run(args);
}
public void run(String[] args) throws IOException {
if (args.length > 0 && "DEBUG_MODE".equals(args[0])) {
in = new BufferedReader(new InputStreamReader(new FileInputStream("input.txt")));
} else {
in = new BufferedReader(new InputStreamReader(System.in));
}
out = new PrintWriter(System.out);
// out = new PrintWriter("output.txt");
// int t = nextInt();
int t = 1;
for (int i = 0; i < t; i++) {
// out.print("Case #" + (i + 1) + ": ");
solve();
}
in.close();
out.flush();
out.close();
}
private int[] nextIntArray(int n) throws IOException {
int[] res = new int[n];
for (int i = 0; i < n; i++) {
res[i] = nextInt();
}
return res;
}
private long[] nextLongArray(int n) throws IOException {
long[] res = new long[n];
for (int i = 0; i < n; i++) {
res[i] = nextInt();
}
return res;
}
private int nextInt() throws IOException {
return Integer.parseInt(nextToken());
}
private long nextLong() throws IOException {
return Long.parseLong(nextToken());
}
private double nextDouble() throws IOException {
return Double.parseDouble(nextToken());
}
private String nextToken() throws IOException {
while (line == null || !line.hasMoreTokens()) {
line = new StringTokenizer(in.readLine());
}
return line.nextToken();
}
private static class Pii {
private int key;
private int value;
public Pii(int key, int value) {
this.key = key;
this.value = value;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Pii pii = (Pii) o;
if (key != pii.key) return false;
return value == pii.value;
}
@Override
public int hashCode() {
int result = key;
result = 31 * result + value;
return result;
}
@Override
public String toString() {
return "Pii{" +
"key=" + key +
", value=" + value +
'}';
}
}
private static class Pair<K, V> {
private K key;
private V value;
public Pair(K key, V value) {
this.key = key;
this.value = value;
}
public K getKey() {
return key;
}
public V getValue() {
return value;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Pair<?, ?> pair = (Pair<?, ?>) o;
if (key != null ? !key.equals(pair.key) : pair.key != null) return false;
return !(value != null ? !value.equals(pair.value) : pair.value != null);
}
@Override
public int hashCode() {
int result = key != null ? key.hashCode() : 0;
result = 31 * result + (value != null ? value.hashCode() : 0);
return result;
}
}
}
In Python3 :
#!/bin/python3
import sys
a0,a1,a2 = input().strip().split(' ')
a0,a1,a2 = [int(a0),int(a1),int(a2)]
b0,b1,b2 = input().strip().split(' ')
b0,b1,b2 = [int(b0),int(b1),int(b2)]
A = (a0>b0) + (a1>b1) + (a2>b2)
B = (a0<b0) + (a1<b1) + (a2<b2)
print(A, B)
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