# Compare the Triplets

### Problem Statement :

```Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.

The rating for Alice's challenge is the triplet a = (a, a, a), and the rating for Bob's challenge is the triplet b = (b, b, b).

The task is to find their comparison points by comparing a with b, a with b, and a with b.

If a[i] > b[i], then Alice is awarded 1 point.
If a[i] < b[i], then Bob is awarded 1 point.
If a[i] = b[i], then neither person receives a point.

Comparison points is the total points a person earned.

Given a and b, determine their respective comparison points.

Example

a = [1, 2, 3]
b = [3, 2, 1]

For elements *0*, Bob is awarded a point because a .
For the equal elements a and b, no points are earned.
Finally, for elements 2, a > b so Alice receives a point.

The return array is [1, 1] with Alice's score first and Bob's second.

Function Description

Complete the function compareTriplets in the editor below.

compareTriplets has the following parameter(s):

int a: Alice's challenge rating
int b: Bob's challenge rating

Return

int: Alice's score is in the first position, and Bob's score is in the second.

Input Format

The first line contains 3 space-separated integers, a, a, and a, the respective values in triplet a.
The second line contains 3 space-separated integers, b, b, and b, the respective values in triplet b.

Constraints

1 ≤ a[i] ≤ 100
1 ≤ b[i] ≤ 100```

### Solution :

```                            ```Solution in C :

In C++ :

#include <bits/stdc++.h>

using namespace std;

#define pb push_back
#define mp make_pair
#define REP(i, n) for (int i = 0; i < (int)(n); ++i)
typedef long long LL;
typedef pair<int, int> PII;

int a, b;

int main() {
REP(i, 3) scanf("%d", a + i);
REP(i, 3) scanf("%d", b + i);
int x = 0, y = 0;
REP(i, 3) if (a[i] > b[i]) {
++x;
} else if (a[i] < b[i]) {
++y;
}
printf("%d %d\n", x, y);
return 0;
}

In C :

int* compareTriplets(int a_count, int* a, int b_count, int* b, int* result_count) {

int  Alice_point = 0,  Bob_point = 0;
for(int i = 0; i<a_count; i++)
{
if(a[i]==b[i])
{

}

if(a[i]>b[i])
{
Alice_point += 1;

}
if(a[i]<b[i])
{
Bob_point += 1;

}

}

*result_count = 2;

static int c;
c  = Alice_point;
c = Bob_point;
return c;

}

In Java:

import java.io.*;
import java.util.*;

public class Solution {
private StringTokenizer line;
private PrintWriter out;

private static final int mm = 1000000007;

public void solve() throws IOException {
int[] a = nextIntArray(3);
int[] b = nextIntArray(3);
int aa = 0;
int bb = 0;
for (int i = 0; i < 3; i++) {
if (a[i] > b[i]) aa++;
else if (a[i] < b[i]) bb++;
}
out.println(aa + " " + bb);
}

public static void main(String[] args) throws IOException {
new Solution().run(args);
}

public void run(String[] args) throws IOException {
if (args.length > 0 && "DEBUG_MODE".equals(args)) {
} else {
}
out = new PrintWriter(System.out);
//        out = new PrintWriter("output.txt");

//        int t = nextInt();
int t = 1;
for (int i = 0; i < t; i++) {
//            out.print("Case #" + (i + 1) + ": ");
solve();
}

in.close();
out.flush();
out.close();
}

private int[] nextIntArray(int n) throws IOException {
int[] res = new int[n];
for (int i = 0; i < n; i++) {
res[i] = nextInt();
}
return res;
}

private long[] nextLongArray(int n) throws IOException {
long[] res = new long[n];
for (int i = 0; i < n; i++) {
res[i] = nextInt();
}
return res;
}

private int nextInt() throws IOException {
return Integer.parseInt(nextToken());
}

private long nextLong() throws IOException {
return Long.parseLong(nextToken());
}

private double nextDouble() throws IOException {
return Double.parseDouble(nextToken());
}

private String nextToken() throws IOException {
while (line == null || !line.hasMoreTokens()) {
}
return line.nextToken();
}

private static class Pii {
private int key;
private int value;

public Pii(int key, int value) {
this.key = key;
this.value = value;
}

@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;

Pii pii = (Pii) o;

if (key != pii.key) return false;
return value == pii.value;

}

@Override
public int hashCode() {
int result = key;
result = 31 * result + value;
return result;
}

@Override
public String toString() {
return "Pii{" +
"key=" + key +
", value=" + value +
'}';
}
}

private static class Pair<K, V> {
private K key;
private V value;

public Pair(K key, V value) {
this.key = key;
this.value = value;
}

public K getKey() {
return key;
}

public V getValue() {
return value;
}

@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;

Pair<?, ?> pair = (Pair<?, ?>) o;

if (key != null ? !key.equals(pair.key) : pair.key != null) return false;
return !(value != null ? !value.equals(pair.value) : pair.value != null);

}

@Override
public int hashCode() {
int result = key != null ? key.hashCode() : 0;
result = 31 * result + (value != null ? value.hashCode() : 0);
return result;
}
}
}

In Python3 :

#!/bin/python3

import sys

a0,a1,a2 = input().strip().split(' ')
a0,a1,a2 = [int(a0),int(a1),int(a2)]
b0,b1,b2 = input().strip().split(' ')
b0,b1,b2 = [int(b0),int(b1),int(b2)]

A = (a0>b0) + (a1>b1) + (a2>b2)
B = (a0<b0) + (a1<b1) + (a2<b2)
print(A, B)```
```

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