Binary Search Tree : Insertion


Problem Statement :


You are given a pointer to the root of a binary search tree and values to be inserted into the tree. Insert the values into their appropriate position in the binary search tree and return the root of the updated binary tree. You just have to complete the function.

Input Format

You are given a function,

Node * insert (Node * root ,int data) {

}
Constraints

No. of nodes in the tree <= 500
Output Format

Return the root of the binary search tree after inserting the value into the tree.



Solution :



title-img


                            Solution in C :

In C++ :



/*
Node is defined as 

typedef struct node
{
   int data;
   node * left;
   node * right;
}node;

*/
#include<queue>
queue<node *> Queue;

node * insert(node * root, int value)
{
   node *n=new node();
    n->data=value;
    n->left=NULL;
    n->right=NULL;
    if(!root){
        root=n;
        return root;
    }
    node *temp=root;   
    while(1){
        if(temp->data > n->data){
            if(temp->left)
                temp=temp->left;
               else{
                temp->left=n;
                break;
            }
        }
        else
            {
            if(temp->right)
                temp=temp->right;
            else
                {
                temp->right=n;
                break;
            }
        }
    }
   return root;
}




In Java :


 /* Node is defined as :
 class Node 
    int data;
    Node left;
    Node right;
    
    */

static Node Insert(Node root,int value)
    {
        if(root == null) 
            {
                root = new Node();
                root.data = value;
        }
        else if(root.data > value) 
            {
                if(root.left == null)
                {
                        Node left = new Node();
                        left.data = value;
                        root.left = left;
                }
                else //keep looking, strictly on left as value is smaller than root
                {
                     Insert(root.left, value);
                }
           
        }
        else
            {
                if(root.right == null) //place for value found
                {
                        Node right = new Node();
                        right.data = value;
                        root.right = right;
                }
                else 
                {
                     Insert(root.right, value);
                }
        }
        return root;
    }





In C :


/* you only have to complete the function given below.  
node is defined as  

struct node {
    
    int data;
    struct node *left;
    struct node *right;
  
};

*/
struct node* insert( struct node* root, int data ) {
    struct node *prev_node = NULL;
    struct node *temp_node = root;

    while (temp_node) {
        prev_node = temp_node;

        if (data < temp_node->data) {
            temp_node = temp_node->left;
        }

        else {
            temp_node = temp_node->right;
        }
    }

    struct node *new_node = malloc(sizeof(struct node));
    new_node->data = data;

    if (!prev_node) {
        root = new_node;
    }

    else {
        if (data < prev_node->data) {
            prev_node->left = new_node;
        }

        else {
            prev_node->right = new_node;
        }
    }
    
    return root;
}







In python3 :



#Node is defined as
#self.left (the left child of the node)
#self.right (the right child of the node)
#self.info (the value of the node)

    def insert(self, val):
        if not self.root:
            self.root = Node(val)
        else:
            node = self.root
            while(True):
                if (node.info>val):
                    if node.left:
                        node = node.left
                    else:
                        node.left = Node(val)
                        return
                else:
                    if node.right:
                        node = node.right
                    else:
                        node.right = Node(val)
                        return
        #Enter you code here.
                        








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