Binary Search Tree : Insertion
Problem Statement :
You are given a pointer to the root of a binary search tree and values to be inserted into the tree. Insert the values into their appropriate position in the binary search tree and return the root of the updated binary tree. You just have to complete the function.
Input Format
You are given a function,
Node * insert (Node * root ,int data) {
}
Constraints
No. of nodes in the tree <= 500
Output Format
Return the root of the binary search tree after inserting the value into the tree.
Solution :
Solution in C :
In C++ :
/*
Node is defined as
typedef struct node
{
int data;
node * left;
node * right;
}node;
*/
#include<queue>
queue<node *> Queue;
node * insert(node * root, int value)
{
node *n=new node();
n->data=value;
n->left=NULL;
n->right=NULL;
if(!root){
root=n;
return root;
}
node *temp=root;
while(1){
if(temp->data > n->data){
if(temp->left)
temp=temp->left;
else{
temp->left=n;
break;
}
}
else
{
if(temp->right)
temp=temp->right;
else
{
temp->right=n;
break;
}
}
}
return root;
}
In Java :
/* Node is defined as :
class Node
int data;
Node left;
Node right;
*/
static Node Insert(Node root,int value)
{
if(root == null)
{
root = new Node();
root.data = value;
}
else if(root.data > value)
{
if(root.left == null)
{
Node left = new Node();
left.data = value;
root.left = left;
}
else //keep looking, strictly on left as value is smaller than root
{
Insert(root.left, value);
}
}
else
{
if(root.right == null) //place for value found
{
Node right = new Node();
right.data = value;
root.right = right;
}
else
{
Insert(root.right, value);
}
}
return root;
}
In C :
/* you only have to complete the function given below.
node is defined as
struct node {
int data;
struct node *left;
struct node *right;
};
*/
struct node* insert( struct node* root, int data ) {
struct node *prev_node = NULL;
struct node *temp_node = root;
while (temp_node) {
prev_node = temp_node;
if (data < temp_node->data) {
temp_node = temp_node->left;
}
else {
temp_node = temp_node->right;
}
}
struct node *new_node = malloc(sizeof(struct node));
new_node->data = data;
if (!prev_node) {
root = new_node;
}
else {
if (data < prev_node->data) {
prev_node->left = new_node;
}
else {
prev_node->right = new_node;
}
}
return root;
}
In python3 :
#Node is defined as
#self.left (the left child of the node)
#self.right (the right child of the node)
#self.info (the value of the node)
def insert(self, val):
if not self.root:
self.root = Node(val)
else:
node = self.root
while(True):
if (node.info>val):
if node.left:
node = node.left
else:
node.left = Node(val)
return
else:
if node.right:
node = node.right
else:
node.right = Node(val)
return
#Enter you code here.
View More Similar Problems
Simple Text Editor
In this challenge, you must implement a simple text editor. Initially, your editor contains an empty string, S. You must perform Q operations of the following 4 types: 1. append(W) - Append W string to the end of S. 2 . delete( k ) - Delete the last k characters of S. 3 .print( k ) - Print the kth character of S. 4 . undo( ) - Undo the last (not previously undone) operation of type 1 or 2,
View Solution →Poisonous Plants
There are a number of plants in a garden. Each of the plants has been treated with some amount of pesticide. After each day, if any plant has more pesticide than the plant on its left, being weaker than the left one, it dies. You are given the initial values of the pesticide in each of the plants. Determine the number of days after which no plant dies, i.e. the time after which there is no plan
View Solution →AND xor OR
Given an array of distinct elements. Let and be the smallest and the next smallest element in the interval where . . where , are the bitwise operators , and respectively. Your task is to find the maximum possible value of . Input Format First line contains integer N. Second line contains N integers, representing elements of the array A[] . Output Format Print the value
View Solution →Waiter
You are a waiter at a party. There is a pile of numbered plates. Create an empty answers array. At each iteration, i, remove each plate from the top of the stack in order. Determine if the number on the plate is evenly divisible ith the prime number. If it is, stack it in pile Bi. Otherwise, stack it in stack Ai. Store the values Bi in from top to bottom in answers. In the next iteration, do the
View Solution →Queue using Two Stacks
A queue is an abstract data type that maintains the order in which elements were added to it, allowing the oldest elements to be removed from the front and new elements to be added to the rear. This is called a First-In-First-Out (FIFO) data structure because the first element added to the queue (i.e., the one that has been waiting the longest) is always the first one to be removed. A basic que
View Solution →Castle on the Grid
You are given a square grid with some cells open (.) and some blocked (X). Your playing piece can move along any row or column until it reaches the edge of the grid or a blocked cell. Given a grid, a start and a goal, determine the minmum number of moves to get to the goal. Function Description Complete the minimumMoves function in the editor. minimumMoves has the following parameter(s):
View Solution →