**Balanced Brackets Sequel - Amazon Top Interview Questions**

### Problem Statement :

Given a string s containing round, curly, and square open and closing brackets, return whether the brackets are balanced. Constraints n ≤ 100,000 where n is the length of s Example 1 Input s = "[(])" Output False Example 2 Input s = "([])[]({})" Output True

### Solution :

` ````
Solution in C++ :
bool solve(string s) {
stack<char> stack;
for (char c : s) {
if (c == '(' || c == '{' || c == '[')
stack.push(c);
else {
if (stack.empty())
return false;
else if (c == ')' && stack.top() != '(')
return false;
else if (c == '}' && stack.top() != '{')
return false;
else if (c == ']' && stack.top() != '[')
return false;
else
stack.pop();
}
}
return stack.empty();
}
```

` ````
Solution in Python :
class Solution:
def solve(self, s):
# The stack to keep track of opening brackets.
stack = []
# Hash map for keeping track of mappings. This keeps the code very clean.
# Also makes adding more types of parenthesis easier
mapping = {")": "(", "}": "{", "]": "["}
for char in s:
# if char is a closing bracket
if char in mapping:
# Pop the top most element else #, the top most element must be an opening bracket
# of the same type
top = stack.pop() if stack else "#"
if mapping[char] != top:
return False
else:
stack.append(char)
# if the stack is empty, we have a valid expression
# the stack wont be empty for cases like (()
return not stack
```

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