# Simple Array Sum

### Problem Statement :

```Given an array of integers, find the sum of its elements.

For example, if the array ar = [1,2,3], 1+2+3 = 6 , so return 6

.
Function Description

Complete the simpleArraySum function in the editor below. It must return the sum of the array elements as an integer.

simpleArraySum has the following parameter(s):

ar: an array of integers

Input Format

The first line contains an integer, n, denoting the size of the array.
The second line contains n space-separated integers representing the array's elements.

Constraints 0 < n, a[i] < = 1000

Output Format

Print the sum of the array's elements as a single integer.```

### Solution :

```                            ```Solution in C :

In C :

int simpleArraySum(int ar_count, int* ar) {
int i;
int sum = 0;
for(i=0;i < ar_count;i++)
{
sum = sum + ar[i];
}
return sum;
}

In Python3:

n = int(input())
nums = list(map(int, input().split()))
sum = 0
for num in nums:
sum += num
print(sum)

In C++ :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {

unsigned long long int N, Sum = 0, i, Num;

cin>>N;

for (i = 1 ; i <= N ; i++)
{
cin>> Num;
Sum += Num;
}

cout<<Sum<<endl;

return 0;
}

In Java :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int num=sc.nextInt();
int sum=0;
for(int i=0;i<num;i++)
sum+=sc.nextInt();
System.out.println(sum);

}
}```
```

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