Simple Array Sum


Problem Statement :


Given an array of integers, find the sum of its elements.

For example, if the array ar = [1,2,3], 1+2+3 = 6 , so return 6

.
Function Description

Complete the simpleArraySum function in the editor below. It must return the sum of the array elements as an integer.

simpleArraySum has the following parameter(s):

    ar: an array of integers

Input Format

The first line contains an integer, n, denoting the size of the array.
The second line contains n space-separated integers representing the array's elements.

Constraints 0 < n, a[i] < = 1000

Output Format

Print the sum of the array's elements as a single integer.



Solution :


                            Solution in C :

In C : 

int simpleArraySum(int ar_count, int* ar) {
    int i;
    int sum = 0;
    for(i=0;i < ar_count;i++)
    {   
         sum = sum + ar[i];
    }
    return sum;
}




In Python3:

n = int(input())
nums = list(map(int, input().split()))
sum = 0
for num in nums:
    sum += num
print(sum)




In C++ :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    
    unsigned long long int N, Sum = 0, i, Num;
    
    cin>>N;
    
    for (i = 1 ; i <= N ; i++)
        {
        cin>> Num;
        Sum += Num;
    }
    
    cout<<Sum<<endl;
       
    return 0;
}




In Java :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
            int num=sc.nextInt();
        int sum=0;
        for(int i=0;i<num;i++)
            sum+=sc.nextInt();
        System.out.println(sum);
 
    }
}
                        




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