Zipped! python
Problem Statement :
zip([iterable, ...])
This function returns a list of tuples. The th tuple contains the th element from each of the argument sequences or iterables.
If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.
Sample Code
>>> print zip([1,2,3,4,5,6],'Hacker')
[(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')]
>>>
>>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1])
[(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)]
>>>
>>> A = [1,2,3]
>>> B = [6,5,4]
>>> C = [7,8,9]
>>> X = [A] + [B] + [C]
>>>
>>> print zip(*X)
[(1, 6, 7), (2, 5, 8), (3, 4, 9)]
Task
The National University conducts an examination of N students in X subjects.
Your task is to compute the average scores of each student.
Average = sum of marks obtained in all the subjects by students / total number of subjects
The format for the general mark sheet is:
Student ID → ___1_____2_____3_____4_____5__
Subject 1 | 89 90 78 93 80
Subject 2 | 90 91 85 88 86
Subject 3 | 91 92 83 89 90.5
|______________________________
Average 90 91 82 90 85.5
Input Format
The first line contains N and X separated by a space.
The next X lines contains the space separated marks obtained by students in a particular subject.
Constraints
0<N<=100
0<X<=100
Output Format
Print the averages of all students on separate lines.
The averages must be correct up to 1 decimal place.
Solution :
Solution in C :
N, X = map(int, input().split())
score = []
for _ in range(X):
score.append(list(map(float, input().split())))
for stud in list(zip(*score)):
print("%.1f" % (sum(stud) / len(stud)
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