**Vector-Sort C++**

### Problem Statement :

You are given integers N .Sort N the integers and print the sorted order. Store the N integers in a vector.Vectors are sequence containers representing arrays that can change in size. Declaration: vector<int>v; (creates an empty vector of integers) Size: int size=v.size(); Pushing an integer into a vector: v.push_back(x);(where x is an integer.The size increases by 1 after this.) Popping the last element from the vector: v.pop_back(); (After this the size decreases by 1) Sorting a vector: sort(v.begin(),v.end()); (Will sort all the elements in the vector) To know more about vectors, Click Here Input Format The first line of the input contains N where N is the number of integers. The next line contains N integers. Constraints 1 <= N <= 10^5 1 <= Vi <= 10^9 , where Vi is the ith integer in the vector. Output Format Print the integers in the sorted order one by one in a single line followed by a space.

### Solution :

` ````
Solution in C :
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int N = 0;
cin>>N;
vector<int> vecInt;
int number = 0;
while (cin>>number)
vecInt.push_back(number);
sort(vecInt.begin(), vecInt.end());
for ( vector<int>::iterator it = vecInt.begin(); it != vecInt.end(); it++)
cout<<*it<<" ";
return 0;
}
```

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