# Vector-Sort C++

### Problem Statement :

```You are given integers N .Sort N the integers and print the sorted order.
Store the N integers in a vector.Vectors are sequence containers representing arrays that can change in size.

Declaration:

vector<int>v; (creates an empty vector of integers)

Size:

int size=v.size();

Pushing an integer into a vector:

v.push_back(x);(where x is an integer.The size increases by 1 after this.)

Popping the last element from the vector:

v.pop_back(); (After this the size decreases by 1)

Sorting a vector:

sort(v.begin(),v.end()); (Will sort all the elements in the vector)

Input Format

The first line of the input contains N where N is the number of integers. The next line contains N integers.

Constraints

1 <= N  <= 10^5
1 <= Vi  <= 10^9 , where Vi is the ith integer in the vector.

Output Format

Print the integers in the sorted order one by one in a single line followed by a space.```

### Solution :

```                            ```Solution in C :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {
int N = 0;
cin>>N;

vector<int> vecInt;
int number = 0;

while (cin>>number)
vecInt.push_back(number);

sort(vecInt.begin(), vecInt.end());

for ( vector<int>::iterator it = vecInt.begin(); it != vecInt.end(); it++)
cout<<*it<<" ";
return 0;
}```
```

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