Two Strings

Problem Statement :

Given two strings, determine if they share a common substring. A substring may be as small as one character.


s1 = 'and'
s2  = 'art'

These share the common substring a.

s1 = 'be'
s2 = 'cat'

These do not share a substring.

Function Description

Complete the function twoStrings in the editor below.

twoStrings has the following parameter(s):

string s1: a string
string s2: another string


string: either YES or NO

Input Format

The first line contains a single integer p, the number of test cases.

The following p pairs of lines are as follows:

The first line contains string s1.
The second line contains string s2.


s1 and s2 consist of characters in the range ascii[a-z].
1  <=  p  <= 10
1  <=  | s1 |, | s2 |  <= 10^5

Output Format

For each pair of strings, return YES or NO.

Solution :


                            Solution in C :

In  C++  :

#include <bits/stdc++.h>
using namespace std;
int main()
    int a; cin >> a;
    for (int g=0;g<a; g++)
        string b,c; cin >> b >> c; map <char,int> k; 
        for (int y=0;y<b.length(); y++) k[b[y]]=1; int counter=0; 
        for (int y=0;y<c.length(); y++) 
            if (k[c[y]]) counter=1; 
        if (counter) cout << "YES" << '\n';
        else cout << "NO" << '\n'; 
    }return 0; 

In   Java  :

import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
      Scanner sc = new Scanner(;
      int t = sc.nextInt();
      while(t-- > 0){
        char[] s1 =;
        char[] s2 =;
        int[] chs = new int[1000];
        for(int i = 0; i < s1.length; i++){
        String result = "NO";
        for(int i = 0; i < s2.length; i++){
            result = "YES";

In   C  :

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int k;
        char str[110000],btr[110000];
        int cn1[500],cn2[500],i,j,t,a,b;
    return 0;

In  Python3  :

a = int(input())
for i in range(a):
    i = (input())
    j = (input())
    setx = set([a for a in i])
    sety = set([y for y in j])
    if setx.intersection(sety) == set():

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