Two Strings


Problem Statement :


Given two strings, determine if they share a common substring. A substring may be as small as one character.

Example

s1 = 'and'
s2  = 'art'


These share the common substring a.

s1 = 'be'
s2 = 'cat'


These do not share a substring.

Function Description

Complete the function twoStrings in the editor below.

twoStrings has the following parameter(s):

string s1: a string
string s2: another string

Returns

string: either YES or NO

Input Format

The first line contains a single integer p, the number of test cases.

The following p pairs of lines are as follows:

The first line contains string s1.
The second line contains string s2.


Constraints

s1 and s2 consist of characters in the range ascii[a-z].
1  <=  p  <= 10
1  <=  | s1 |, | s2 |  <= 10^5

Output Format

For each pair of strings, return YES or NO.


Solution :



title-img 


                            Solution in C :

In  C++  :




#include <bits/stdc++.h>
using namespace std;
int main()
{
    int a; cin >> a;
    for (int g=0;g<a; g++)
    {
        string b,c; cin >> b >> c; map <char,int> k; 
        for (int y=0;y<b.length(); y++) k[b[y]]=1; int counter=0; 
        for (int y=0;y<c.length(); y++) 
        {
            if (k[c[y]]) counter=1; 
        }
        if (counter) cout << "YES" << '\n';
        else cout << "NO" << '\n'; 
    }return 0; 
}







In   Java  :







import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
      Scanner sc = new Scanner(System.in);
      int t = sc.nextInt();
      while(t-- > 0){
        char[] s1 = sc.next().toCharArray();
        char[] s2 = sc.next().toCharArray();
        int[] chs = new int[1000];
        for(int i = 0; i < s1.length; i++){
          chs[s1[i]]++;
        }
        String result = "NO";
        for(int i = 0; i < s2.length; i++){
          if(chs[s2[i]]>0){
            result = "YES";
            break;
          }
        }
        System.out.println(result);
      }
    }
}








In   C  :








#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int k;
    scanf("%d",&k);
    while(k>0)
        {
        char str[110000],btr[110000];
        int cn1[500],cn2[500],i,j,t,a,b;
        for(i=0;i<500;i++)
            {
            cn1[i]=0;
            cn2[i]=0;
        }
        scanf("%s",str);
        scanf("%s",btr);
        a=strlen(str);
        b=strlen(btr);
        for(i=0;i<a;i++)
            {
            cn1[str[i]]++;
        }
        for(i=0;i<b;i++)
            {
            cn2[btr[i]]++;
        }
        t=0;
        for(i=0;i<500;i++)
            {
            if(cn1[i]*cn2[i]>0)
                {
                t=1;
                break;
            }
        }
        if(t)
            {
            printf("YES\n");
        }
        else
            {
            printf("NO\n");
        }
        k--;
    }
    return 0;
}








In  Python3  :





a = int(input())
for i in range(a):
    i = (input())
    j = (input())
    setx = set([a for a in i])
    sety = set([y for y in j])
    if setx.intersection(sety) == set():
        print("NO")
    else:
        print("YES")








View More Similar Problems

Array and simple queries

Given two numbers N and M. N indicates the number of elements in the array A[](1-indexed) and M indicates number of queries. You need to perform two types of queries on the array A[] . You are given queries. Queries can be of two types, type 1 and type 2. Type 1 queries are represented as 1 i j : Modify the given array by removing elements from i to j and adding them to the front. Ty

View Solution →

Median Updates

The median M of numbers is defined as the middle number after sorting them in order if M is odd. Or it is the average of the middle two numbers if M is even. You start with an empty number list. Then, you can add numbers to the list, or remove existing numbers from it. After each add or remove operation, output the median. Input: The first line is an integer, N , that indicates the number o

View Solution →

Maximum Element

You have an empty sequence, and you will be given N queries. Each query is one of these three types: 1 x -Push the element x into the stack. 2 -Delete the element present at the top of the stack. 3 -Print the maximum element in the stack. Input Format The first line of input contains an integer, N . The next N lines each contain an above mentioned query. (It is guaranteed that each

View Solution →

Balanced Brackets

A bracket is considered to be any one of the following characters: (, ), {, }, [, or ]. Two brackets are considered to be a matched pair if the an opening bracket (i.e., (, [, or {) occurs to the left of a closing bracket (i.e., ), ], or }) of the exact same type. There are three types of matched pairs of brackets: [], {}, and (). A matching pair of brackets is not balanced if the set of bra

View Solution →

Equal Stacks

ou have three stacks of cylinders where each cylinder has the same diameter, but they may vary in height. You can change the height of a stack by removing and discarding its topmost cylinder any number of times. Find the maximum possible height of the stacks such that all of the stacks are exactly the same height. This means you must remove zero or more cylinders from the top of zero or more of

View Solution →

Game of Two Stacks

Alexa has two stacks of non-negative integers, stack A = [a0, a1, . . . , an-1 ] and stack B = [b0, b1, . . . , b m-1] where index 0 denotes the top of the stack. Alexa challenges Nick to play the following game: In each move, Nick can remove one integer from the top of either stack A or stack B. Nick keeps a running sum of the integers he removes from the two stacks. Nick is disqualified f

View Solution →