# Tower Breakers

### Problem Statement :

```Two players are playing a game of Tower Breakers! Player  always moves first, and both players always play optimally.The rules of the game are as follows:

Initially there are  towers.
Each tower is of height .
The players move in alternating turns.
In each turn, a player can choose a tower of height  and reduce its height to , where  and  evenly divides .
If the current player is unable to make a move, they lose the game.
Given the values of  and , determine which player will win. If the first player wins, return . Otherwise, return .

Function Description

Complete the towerBreakers function in the editor below.

towerBreakers has the following paramter(s):

int n: the number of towers
int m: the height of each tower
Returns

int: the winner of the game

Input Format

The first line contains a single integer , the number of test cases.
Each of the next  lines describes a test case in the form of  space-separated integers,  and .```

### Solution :

```                            ```Solution in C :

In  C  :

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
long int cnt(long int a,int k)
{
if(k*k>a)
return a!=1;
return a%k?cnt(a,k+1):1+cnt(a/k,k+1);
}
int main() {

int t;
long int n,m,s;
char a[2]={'2','1'};
scanf("%d",&t);
while(t--)
{
s=0;
scanf("%ld%ld",&n,&m);
while(m%4==0)
m/=2;
if(n%2==0)
s=0;
else
s^=cnt(m,2);
printf("%c\n",a[!!s]);
}
return 0;
}```
```

```                        ```Solution in C++ :

In  C++  :

#include <bits/stdc++.h>
typedef long long ll;
typedef unsigned long long ull;
using namespace std;

int main()
{
long nTest,n,m;
scanf("%ld",&nTest);
while (nTest--)
{
scanf("%ld%ld",&n,&m);
if (m==1) puts("2");
else puts((n&1)?"1":"2");
}
}```
```

```                        ```Solution in Java :

In  Java :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

private static int numPrimeFactors(int n) {
for (int i=2; i<=n; i++) {
if (n%i == 0) {
n /= i;
i = 1;
}
}
}

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
for (int t=0; t<T; t++) {
int n = sc.nextInt();
int m = sc.nextInt();
if (m == 1) {
System.out.println(2);
continue;
}
if (n%2 == 0) {
System.out.println(2);
} else {
System.out.println(1);
}

}

}
}```
```

```                        ```Solution in Python :

In  Python3 :

test = int(input())
for _ in range(test):
n,m = map(int,input().strip().split())
if m==1:
print(2)
else:
if n%2==1:
print(1)
else:
print(2)```
```

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