**Super Reduced String**

### Problem Statement :

Reduce a string of lowercase characters in range ascii[‘a’..’z’]by doing a series of operations. In each operation, select a pair of adjacent letters that match, and delete them. Delete as many characters as possible using this method and return the resulting string. If the final string is empty, return Empty String Function Description Complete the superReducedString function in the editor below. superReducedString has the following parameter(s): string s: a string to reduce Returns string: the reduced string or Empty String Input Format A single string, s. Constraints 1 <= len of s <= 100 Sample Input 0 aaabccddd Sample Output 0 abd

### Solution :

` ````
Solution in C :
In C++ :
#include<iostream>
#include<vector>
#include<string>
#include<algorithm>
#include<cstdio>
#include<numeric>
#include<cstring>
#include<ctime>
#include<cstdlib>
#include<set>
#include<map>
#include<unordered_map>
#include<unordered_set>
#include<list>
#include<cmath>
#include<bitset>
#include<cassert>
#include<queue>
#include<stack>
#include<deque>
#include<cassert>
using namespace std;
typedef long long ll;
typedef long double ld;
int main()
{
//freopen("input.txt", "r", stdin);
//freopen("output.txt", "w", stdout);
string s;
cin >> s;
vector<char>st;
for (int i = 0; i < (int)s.length(); i++)
{
if (!st.empty() && st.back() == s[i])
{
st.pop_back();
}
else
{
st.push_back(s[i]);
}
}
if (st.empty())
{
printf("Empty String\n");
}
else
{
for (int i = 0; i < (int)st.size(); i++)
{
printf("%c", st[i]);
}
printf("\n");
}
return 0;
}
In Java :
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String S = in.nextLine();
boolean changed = false;
do{
changed = false;
for (int i = 0; i < S.length(); i++){
if (i == S.length() - 1) continue;
if (S.charAt(i) == S.charAt(i+1)){
changed = true;
S = S.substring(0,i) + S.substring(i+2);
}
}
}while(changed);
if (S.equals("")) System.out.println("Empty String");
else System.out.println(S);
}
}
In C :
#include<stdio.h>
typedef unsigned u;
char S[111];u l=1;
int main()
{
char c;
while((c=getchar())<'a');
do
{
S[l]=c;
if(S[l]==S[l-1])--l;
else++l;
}
while((c=getchar())>='a');
S[l]='\0';
printf("%s\n",l-1?S+1:"Empty String");
return 0;
}
In Python3 :
s = input()
while True:
for i in range(len(s)-1):
if s[i] == s[i+1]:
s = s[:i]+s[i+2:]
break
else:
break
print(s if s else "Empty String")
```

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