Super Reduced String

                            Solution in C :

In   C++   :







#include<iostream>
#include<vector>
#include<string>
#include<algorithm>
#include<cstdio>
#include<numeric>
#include<cstring>
#include<ctime>
#include<cstdlib>
#include<set>
#include<map>
#include<unordered_map>
#include<unordered_set>
#include<list>
#include<cmath>
#include<bitset>
#include<cassert>
#include<queue>
#include<stack>
#include<deque>
#include<cassert>
using namespace std;
typedef long long ll;
typedef long double ld;
int main()
{
	//freopen("input.txt", "r", stdin);
	//freopen("output.txt", "w", stdout);
	string s;
	cin >> s;
	vector<char>st;
	for (int i = 0; i < (int)s.length(); i++)
	{
		if (!st.empty() && st.back() == s[i])
		{
			st.pop_back();
		}
		else
		{
			st.push_back(s[i]);
		}
	}
	if (st.empty())
	{
		printf("Empty String\n");
	}
	else
	{
		for (int i = 0; i < (int)st.size(); i++)
		{
			printf("%c", st[i]);
		}
		printf("\n");
	}
	return 0;
}








In    Java   :





import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
      
        Scanner in = new Scanner(System.in);
        String S = in.nextLine();
        boolean changed = false;
        do{
            changed = false;
            for (int i = 0; i < S.length(); i++){
                if (i == S.length() - 1) continue;
                if (S.charAt(i) == S.charAt(i+1)){
                    changed = true;
                    S = S.substring(0,i) + S.substring(i+2);
                }
            }
        }while(changed);
        if (S.equals("")) System.out.println("Empty String");
        else System.out.println(S);
    }
}








In    C  :






#include<stdio.h>
typedef unsigned u;
char S[111];u l=1;
int main()
{
	char c;
	while((c=getchar())<'a');
	do
	{
		S[l]=c;
		if(S[l]==S[l-1])--l;
		else++l;
	}
	while((c=getchar())>='a');
	S[l]='\0';
	printf("%s\n",l-1?S+1:"Empty String");
	return 0;
}








In   Python3 :






s = input()
while True:
    for i in range(len(s)-1):
        if s[i] == s[i+1]:
            s = s[:i]+s[i+2:]
            break
    else:
        break
print(s if s else "Empty String")