Solve Me First
Problem Statement :
Complete the function solveMeFirst to compute the sum of two integers.
Function prototype:
int solveMeFirst(int a, int b);
where,
a is the first integer input.
b is the second integer input
Return values
sum of the above two integers
Solution :
Solution in C :
In C :
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int solveMeFirst(int a, int b) {
int result = a + b ;
return result;
}
int main() {
int num1,num2;
scanf("%d %d",&num1,&num2);
int sum;
sum = solveMeFirst(num1,num2);
printf("%d",sum);
return 0;
}
In C++:
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int solveMeFirst(int a, int b) {
return a+b;
}
int main() {
int num1, num2;
int sum;
cin>>num1>>num2;
sum = solveMeFirst(num1,num2);
cout<<sum;
return 0;
}
In Java:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
static int solveMeFirst(int a, int b) {
return a+b;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int _a;
_a = in.nextInt();
int _b;
_b = in.nextInt();
int sum;
sum = solveMeFirst(_a, _b);
System.out.println(sum);
}
}
In Python3:
def solveMeFirst(a,b):
return a+b
num1 = int(input())
num2 = int(input())
res = solveMeFirst(num1,num2)
print (res)
View More Similar Problems
Contacts
We're going to make our own Contacts application! The application must perform two types of operations: 1 . add name, where name is a string denoting a contact name. This must store name as a new contact in the application. find partial, where partial is a string denoting a partial name to search the application for. It must count the number of contacts starting partial with and print the co
View Solution →No Prefix Set
There is a given list of strings where each string contains only lowercase letters from a - j, inclusive. The set of strings is said to be a GOOD SET if no string is a prefix of another string. In this case, print GOOD SET. Otherwise, print BAD SET on the first line followed by the string being checked. Note If two strings are identical, they are prefixes of each other. Function Descriptio
View Solution →Cube Summation
You are given a 3-D Matrix in which each block contains 0 initially. The first block is defined by the coordinate (1,1,1) and the last block is defined by the coordinate (N,N,N). There are two types of queries. UPDATE x y z W updates the value of block (x,y,z) to W. QUERY x1 y1 z1 x2 y2 z2 calculates the sum of the value of blocks whose x coordinate is between x1 and x2 (inclusive), y coor
View Solution →Direct Connections
Enter-View ( EV ) is a linear, street-like country. By linear, we mean all the cities of the country are placed on a single straight line - the x -axis. Thus every city's position can be defined by a single coordinate, xi, the distance from the left borderline of the country. You can treat all cities as single points. Unfortunately, the dictator of telecommunication of EV (Mr. S. Treat Jr.) do
View Solution →Subsequence Weighting
A subsequence of a sequence is a sequence which is obtained by deleting zero or more elements from the sequence. You are given a sequence A in which every element is a pair of integers i.e A = [(a1, w1), (a2, w2),..., (aN, wN)]. For a subseqence B = [(b1, v1), (b2, v2), ...., (bM, vM)] of the given sequence : We call it increasing if for every i (1 <= i < M ) , bi < bi+1. Weight(B) =
View Solution →Kindergarten Adventures
Meera teaches a class of n students, and every day in her classroom is an adventure. Today is drawing day! The students are sitting around a round table, and they are numbered from 1 to n in the clockwise direction. This means that the students are numbered 1, 2, 3, . . . , n-1, n, and students 1 and n are sitting next to each other. After letting the students draw for a certain period of ti
View Solution →