**Shortest Sublist to Sort - Google Top Interview Questions**

### Problem Statement :

Given a list of integers nums, return the length of the shortest sublist in nums which if sorted would make nums sorted in ascending order. Constraints n ≤ 100,000 where n is the length of nums Example 1 Input nums = [0, 1, 4, 3, 8, 9] Output 2 Explanation Sorting the sublist [4, 3] would get us [0, 1, 3, 4, 8, 9] Example 2 Input nums = [5, 4, 3, 2, 8, 9] Output 4 Explanation Sorting the sublist [5, 4, 3, 2] would get us [2, 3, 4, 5, 8, 9] Example 3 Input nums = [1, 2, 3, 5, 9, 8, 5] Output 3 Explanation Sorting the sublist [9, 8, 5] would get us [1, 2, 3, 5, 5, 8, 9]

### Solution :

` ````
Solution in C++ :
int solve(vector<int>& nums) {
int left, right, lmax, rmin, N;
N = nums.size();
left = right = -1;
lmax = INT_MIN;
rmin = INT_MAX;
for (int i = 0; i < N; ++i) {
if (nums[i] >= lmax)
lmax = nums[i];
else
right = i;
if (nums[N - i - 1] <= rmin)
rmin = nums[N - i - 1];
else
left = N - i - 1;
}
if (left == -1) return 0;
return right - left + 1;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public int solve(int[] nums) {
int[] minRight = new int[nums.length];
int[] maxLeft = new int[nums.length];
for (int i = 0; i < nums.length; i++) {
maxLeft[i] = (i == 0) ? nums[i] : Math.max(maxLeft[i - 1], nums[i]);
minRight[nums.length - 1 - i] = (nums.length - 1 - i == nums.length - 1)
? nums[nums.length - 1]
: Math.min(minRight[nums.length - i], nums[nums.length - 1 - i]);
}
int start = -1, end = -1;
for (int i = 0; i < nums.length; i++) {
if (nums[i] != minRight[i] || nums[i] != maxLeft[i]) {
start = i;
break;
}
}
if (start == -1)
return 0;
for (int i = nums.length - 1; i >= 0; i--) {
if (nums[i] != minRight[i] || nums[i] != maxLeft[i]) {
end = i;
break;
}
}
return end - start + 1;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, nums):
if not nums:
return 0
left_max = nums[0]
n = len(nums)
end = -1
for i in range(1, n):
if nums[i] < left_max:
end = i
left_max = max(left_max, nums[i])
if end == -1:
return 0
right_min = nums[-1]
start = -1
for i in range(n - 2, -1, -1):
if nums[i] > right_min:
start = i
right_min = min(right_min, nums[i])
return end - start + 1
```

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