Set Mutations Python


Problem Statement :


We have seen the applications of union, intersection, difference and symmetric difference operations, but these operations do not make any changes or mutations to the set.

We can use the following operations to create mutations to a set:

.update() or |=
Update the set by adding elements from an iterable/another set.

>>> H = set("Hacker")
>>> R = set("Rank")
>>> H.update(R)
>>> print H
set(['a', 'c', 'e', 'H', 'k', 'n', 'r', 'R'])


.intersection_update() or &=
Update the set by keeping only the elements found in it and an iterable/another set.

>>> H = set("Hacker")
>>> R = set("Rank")
>>> H.intersection_update(R)
>>> print H
set(['a', 'k'])
.difference_update() or -=
Update the set by removing elements found in an iterable/another set.

>>> H = set("Hacker")
>>> R = set("Rank")
>>> H.difference_update(R)
>>> print H
set(['c', 'e', 'H', 'r'])


.symmetric_difference_update() or ^=
Update the set by only keeping the elements found in either set, but not in both.

>>> H = set("Hacker")
>>> R = set("Rank")
>>> H.symmetric_difference_update(R)
>>> print H
set(['c', 'e', 'H', 'n', 'r', 'R'])


TASK
You are given a set A and N number of other sets. These N number of sets have to perform some specific mutation operations on set A.

Your task is to execute those operations and print the sum of elements from set A.


Input Format

The first line contains the number of elements in set A.
The second line contains the space separated list of elements in set A.
The third line contains integer N, the number of other sets.
The next 2*N lines are divided into N parts containing two lines each.
The first line of each part contains the space separated entries of the operation name and the length of the other set.
The second line of each part contains space separated list of elements in the other set.

0< len(set(A))<1000 
0< len(otherSets) <100
0<N<100


Output Format

Output the sum of elements in set A.



Solution :



title-img


                            Solution in C :

_ = input()
a = set(int(x) for x in input().split(' '))

n = int(input())
for _ in range(n):
    op, _ = input().split(' ')
    b = set(int(x) for x in input().split(' '))
    if op == "update":
        a |= b
    elif op == "intersection_update":
        a &= b
    elif op == "difference_update":
        a -= b
    elif op == "symmetric_difference_update":
        a ^= b

print(sum(a))
                        








View More Similar Problems

QHEAP1

This question is designed to help you get a better understanding of basic heap operations. You will be given queries of types: " 1 v " - Add an element to the heap. " 2 v " - Delete the element from the heap. "3" - Print the minimum of all the elements in the heap. NOTE: It is guaranteed that the element to be deleted will be there in the heap. Also, at any instant, only distinct element

View Solution →

Jesse and Cookies

Jesse loves cookies. He wants the sweetness of all his cookies to be greater than value K. To do this, Jesse repeatedly mixes two cookies with the least sweetness. He creates a special combined cookie with: sweetness Least sweet cookie 2nd least sweet cookie). He repeats this procedure until all the cookies in his collection have a sweetness > = K. You are given Jesse's cookies. Print t

View Solution →

Find the Running Median

The median of a set of integers is the midpoint value of the data set for which an equal number of integers are less than and greater than the value. To find the median, you must first sort your set of integers in non-decreasing order, then: If your set contains an odd number of elements, the median is the middle element of the sorted sample. In the sorted set { 1, 2, 3 } , 2 is the median.

View Solution →

Minimum Average Waiting Time

Tieu owns a pizza restaurant and he manages it in his own way. While in a normal restaurant, a customer is served by following the first-come, first-served rule, Tieu simply minimizes the average waiting time of his customers. So he gets to decide who is served first, regardless of how sooner or later a person comes. Different kinds of pizzas take different amounts of time to cook. Also, once h

View Solution →

Merging Communities

People connect with each other in a social network. A connection between Person I and Person J is represented as . When two persons belonging to different communities connect, the net effect is the merger of both communities which I and J belongs to. At the beginning, there are N people representing N communities. Suppose person 1 and 2 connected and later 2 and 3 connected, then ,1 , 2 and 3 w

View Solution →

Components in a graph

There are 2 * N nodes in an undirected graph, and a number of edges connecting some nodes. In each edge, the first value will be between 1 and N, inclusive. The second node will be between N + 1 and , 2 * N inclusive. Given a list of edges, determine the size of the smallest and largest connected components that have or more nodes. A node can have any number of connections. The highest node valu

View Solution →