# Rectangular Overlap - Amazon Top Interview Questions

### Problem Statement :

```You are given two lists of integers rect0 and rect1 representing coordinates (x0, y0, x1, y1) of two rectangles. (x0, y0) is the bottom left coordinate and (x1, y1) is the upper right coordinate.

Return whether the two rectangles overlap.

Note: if two rectangles touch only in their perimeters, they don't overlap.

Example 1

Input
rect0 = [0, 0, 10, 10]
rect1 = [10, 10, 30, 30]

Output
False

Example 2

Input
rect0 = [0, 0, 10, 10]
rect1 = [5, 5, 30, 30]

Output
True```

### Solution :

```                        ```Solution in C++ :

bool solve(vector<int>& rect0, vector<int>& rect1) {
return !(rect0[3] <= rect1[1] || rect1[3] <= rect0[1] || rect0[2] <= rect1[0] ||
rect1[2] <= rect0[0]);
}```
```

```                        ```Solution in Java :

import java.util.*;

class Solution {
public boolean solve(int[] rect0, int[] rect1) {
int x1 = Math.max(rect0[0], rect1[0]);
int y1 = Math.max(rect0[1], rect1[1]);
int x2 = Math.min(rect0[2], rect1[2]);
int y2 = Math.min(rect0[3], rect1[3]);
if (x1 >= x2 || y1 >= y2)
return false;
return true;
}
}```
```

```                        ```Solution in Python :

class Solution:
def solve(self, rect0, rect1):
return not (
rect1[0] >= rect0[2]
or rect0[0] >= rect1[2]
or rect1[1] >= rect0[3]
or rect0[1] >= rect1[3]
)```
```

## Tree: Preorder Traversal

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## Tree: Postorder Traversal

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## Tree: Inorder Traversal

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## Tree: Level Order Traversal

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