**Insert a Node at the Tail of a Linked List**

### Problem Statement :

You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Input Format: You have to complete the SinglyLinkedListNode insertAtTail(SinglyLinkedListNode head, int data) method. It takes two arguments: the head of the linked list and the integer to insert at tail. You should not read any input from the stdin/console. The input is handled by code editor and is as follows: The first line contains an integer n, denoting the elements of the linked list. The next n lines contain an integer each, denoting the element that needs to be inserted at tail. Constraints: 1. 1<=n<=1000 2. 1<=list[i]<=1000

### Solution :

` ````
Solution in C :
In C:
// The following part of code is all you need to complete the challenge in
//hackerrank. Rest is already coded there.
SinglyLinkedListNode* insertNodeAtTail(SinglyLinkedListNode* head, int data) {
SinglyLinkedListNode* tem = head;
SinglyLinkedListNode * t = (SinglyLinkedList*)malloc(sizeof(SinglyLinkedList));
t->data = data;
t->next = NULL;
if(head == NULL){
head = t;
return head;
}
while(tem->next != NULL){
tem = tem->next;
}
tem->next = t;
return head;
}
In C++:
// The following function is all you need to complete the challenge in
//hackerrank platform
Node* Insert(Node *head,int data)
{
Node * temp=head;
Node * newN=new Node;
newN->next=NULL;
newN->data=data;
if(temp==NULL)
return newN;
while(temp->next!=NULL)
temp=temp->next;
temp->next=newN;
return head;
}
In Java:
//The following method is all you need to complete the challenge in
//hackerrank platform
static SinglyLinkedListNode insertNodeAtTail(SinglyLinkedListNode head, int data) {
SinglyLinkedListNode newNode = new SinglyLinkedListNode(data);
if(head == null){
return newNode;
}
SinglyLinkedListNode cur = head;
while(cur.next != null){
cur = cur.next;
}
cur.next = newNode;
return head;
}
In Python 3:
# The following method is all that id needed to complete the
# challenge in hackerrank.
def Insert(head, data):
if head is None:
return Node(data)
pnt = head
while pnt.next:
pnt = pnt.next
pnt.next = Node(data)
return head
```

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