Insert a Node at the Tail of a Linked List


Problem Statement :


You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty.


Input Format:

You have to complete the SinglyLinkedListNode insertAtTail(SinglyLinkedListNode head, int data) method. It takes two arguments: the head of the linked list and the integer to insert at tail. You should not read any input from the stdin/console.

The input is handled by code editor and is as follows:
The first line contains an integer n, denoting the elements of the linked list.
The next n lines contain an integer each, denoting the element that needs to be inserted at tail.


Constraints:
    1. 1<=n<=1000
    2. 1<=list[i]<=1000


Solution :



title-img 


                            Solution in C :

In C:

// The following part of code is all you need to complete the challenge in
//hackerrank. Rest is already coded there.

SinglyLinkedListNode* insertNodeAtTail(SinglyLinkedListNode* head, int data) {
         SinglyLinkedListNode* tem = head;
         SinglyLinkedListNode * t = (SinglyLinkedList*)malloc(sizeof(SinglyLinkedList));
         
         t->data = data;
         t->next = NULL;
    if(head == NULL){
        head = t;
        return head;
    }
         while(tem->next != NULL){
             tem = tem->next;
         }
        tem->next = t;
     return head;

}







In C++:

// The following function is all you need to complete the challenge in 
//hackerrank platform 

Node* Insert(Node *head,int data)
{
    Node * temp=head;
    Node * newN=new Node;
    newN->next=NULL;
    newN->data=data;
    if(temp==NULL)
        return newN;
    while(temp->next!=NULL)
        temp=temp->next;
    temp->next=newN;
    return head;
}







In Java:

//The following method is all you need to complete the challenge in 
//hackerrank platform

 static SinglyLinkedListNode insertNodeAtTail(SinglyLinkedListNode head, int data) {
        SinglyLinkedListNode newNode = new SinglyLinkedListNode(data);
        if(head == null){
            return newNode;
        }
        SinglyLinkedListNode cur = head;
        while(cur.next != null){
            cur = cur.next; 
        }
        cur.next = newNode;
        return head;
    }







In Python 3:

# The following method is all that id needed to complete the
# challenge in hackerrank.

def Insert(head, data):
    if head is None:
        return Node(data)
    pnt = head
    while pnt.next:
        pnt = pnt.next
    pnt.next = Node(data)
    return head








View More Similar Problems

Sparse Arrays

There is a collection of input strings and a collection of query strings. For each query string, determine how many times it occurs in the list of input strings. Return an array of the results. Example: strings=['ab', 'ab', 'abc'] queries=['ab', 'abc', 'bc'] There are instances of 'ab', 1 of 'abc' and 0 of 'bc'. For each query, add an element to the return array, results=[2,1,0]. Fun

View Solution →

Array Manipulation

Starting with a 1-indexed array of zeros and a list of operations, for each operation add a value to each of the array element between two given indices, inclusive. Once all operations have been performed, return the maximum value in the array. Example: n=10 queries=[[1,5,3], [4,8,7], [6,9,1]] Queries are interpreted as follows: a b k 1 5 3 4 8 7 6 9 1 Add the valu

View Solution →

Print the Elements of a Linked List

This is an to practice traversing a linked list. Given a pointer to the head node of a linked list, print each node's data element, one per line. If the head pointer is null (indicating the list is empty), there is nothing to print. Function Description: Complete the printLinkedList function in the editor below. printLinkedList has the following parameter(s): 1.SinglyLinkedListNode

View Solution →

Insert a Node at the Tail of a Linked List

You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Input Format: You have to complete the SinglyLink

View Solution →

Insert a Node at the head of a Linked List

Given a pointer to the head of a linked list, insert a new node before the head. The next value in the new node should point to head and the data value should be replaced with a given value. Return a reference to the new head of the list. The head pointer given may be null meaning that the initial list is empty. Function Description: Complete the function insertNodeAtHead in the editor below

View Solution →

Insert a node at a specific position in a linked list

Given the pointer to the head node of a linked list and an integer to insert at a certain position, create a new node with the given integer as its data attribute, insert this node at the desired position and return the head node. A position of 0 indicates head, a position of 1 indicates one node away from the head and so on. The head pointer given may be null meaning that the initial list is e

View Solution →