Print the Elements of a Linked List


Problem Statement :


This is an to practice traversing a linked list. Given a pointer to the head node of a linked list, print each node's data element, one per line. If the head pointer is null (indicating the list is empty), there is nothing to print.

Function Description:

Complete the printLinkedList function in the editor below.

printLinkedList has the following parameter(s):
      1.SinglyLinkedListNode head: a reference to the head of the list

Print:
     1. For each node, print its  value on a new line (console.log in Javascript).


Input Format:

The first line of input contains n, the number of elements in the linked list.
The next n lines contain one element each, the data values for each node.

Note: Do not read any input from stdin/console. Complete the printLinkedList function in the editor below.


Constraints:
    1. 1<=n<=1000
    2. 1<=list[i]<=1000



Solution :


                            Solution in C :

In C:
//In hacker rank as the solution the program is too big 
//all u need is to code this function.

void printLinkedList(SinglyLinkedListNode* head) {

SinglyLinkedListNode* ptr=head;
    while(ptr!=NULL)
    {
        printf("%d\n",ptr->data);
        ptr=ptr->next;
    }

}







In C++:
//The rest of the code is already coded.
//As the code is too big all you need is complete the following part.

void printLinkedList(SinglyLinkedListNode* head) {

     while(head!=NULL)
     {
         cout << head->data << "\n";
         head = head->next;
     }
}









In Java:
//The following part is all you to complete, the rest is
//already present in hackerrank 

 static void printLinkedList(SinglyLinkedListNode head) {
        while(head != null) { System.out.println(head.data); head = head.next;}

    }






In Python 3:

# The following part of code is all you need to 
# complete the challenge in hacker rank

def printLinkedList(head):
    temp = head
    while (temp.next != None):
        print(temp.data)
        temp = temp.next
    print(temp.data)
                        




View More Similar Problems

Tree : Top View

Given a pointer to the root of a binary tree, print the top view of the binary tree. The tree as seen from the top the nodes, is called the top view of the tree. For example : 1 \ 2 \ 5 / \ 3 6 \ 4 Top View : 1 -> 2 -> 5 -> 6 Complete the function topView and print the resulting values on a single line separated by space.

View Solution →

Tree: Level Order Traversal

Given a pointer to the root of a binary tree, you need to print the level order traversal of this tree. In level-order traversal, nodes are visited level by level from left to right. Complete the function levelOrder and print the values in a single line separated by a space. For example: 1 \ 2 \ 5 / \ 3 6 \ 4 F

View Solution →

Binary Search Tree : Insertion

You are given a pointer to the root of a binary search tree and values to be inserted into the tree. Insert the values into their appropriate position in the binary search tree and return the root of the updated binary tree. You just have to complete the function. Input Format You are given a function, Node * insert (Node * root ,int data) { } Constraints No. of nodes in the tree <

View Solution →

Tree: Huffman Decoding

Huffman coding assigns variable length codewords to fixed length input characters based on their frequencies. More frequent characters are assigned shorter codewords and less frequent characters are assigned longer codewords. All edges along the path to a character contain a code digit. If they are on the left side of the tree, they will be a 0 (zero). If on the right, they'll be a 1 (one). Only t

View Solution →

Binary Search Tree : Lowest Common Ancestor

You are given pointer to the root of the binary search tree and two values v1 and v2. You need to return the lowest common ancestor (LCA) of v1 and v2 in the binary search tree. In the diagram above, the lowest common ancestor of the nodes 4 and 6 is the node 3. Node 3 is the lowest node which has nodes and as descendants. Function Description Complete the function lca in the editor b

View Solution →

Swap Nodes [Algo]

A binary tree is a tree which is characterized by one of the following properties: It can be empty (null). It contains a root node only. It contains a root node with a left subtree, a right subtree, or both. These subtrees are also binary trees. In-order traversal is performed as Traverse the left subtree. Visit root. Traverse the right subtree. For this in-order traversal, start from

View Solution →