Print in Reverse

Problem Statement :

Given a pointer to the head of a singly-linked list, print each data value from the reversed list. If the given list is empty, do not print anything.


 head* refers to the linked list with data values 1->2->3->Null

Print the following:

Function Description:

Complete the reversePrint function in the editor below.

reversePrint has the following parameters:

SinglyLinkedListNode pointer head: a reference to the head of the list


The data values of each node in the reversed list.

Input Format:

The first line of input contains t, the number of test cases.

The input of each test case is as follows:
          1. The first line contains an integer n, the number of elements in the list.
          2. Each of the next n lines contains a data element for a list node.

          1.   1<=n<=1000
          2.   1<=list[i]<=1000

Solution :


                            Solution in C :

In C:

//the following fuction is all that is needed to complete the 
//challenge in hackerrank platform.

void reversePrint(SinglyLinkedListNode* head) {
SinglyLinkedListNode* current=head,*next,*prev=NULL;
    {   next=current->next;
    SinglyLinkedListNode* temp=head;


In C++:

//the following fuction is all that is needed to complete the 
//challenge in hackerrank platform.

void ReversePrint(Node *head)
  // This is a "method-only" submission. 
  // You only need to complete this method. 

In Java: 

//the following method is all that is needed to complete the
//challenge in hackerrank platform.

  static void reversePrint(SinglyLinkedListNode head) {
        if( != null) {

In Python 3 :

//the following method is all that is needed to complete the
//challenge in hackerrank platform.

def ReversePrint(head):
    if head is None:

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