**Permute to Make List Larger - Facebook Top Interview Questions**

### Problem Statement :

You are given two lists of integers a and b, both of the same length. Given that you can first permute a in any order, return the maximum number of indices where a[i] > b[i]. Constraints n ≤ 100,000 where n is the length of a and b Example 1 Input a = [3, 5, 8, 1] b = [4, 7, 2, 1] Output 3 Explanation If we permute a to [5, 8, 3, 1].

### Solution :

` ````
Solution in C++ :
int solve(vector<int>& a, vector<int>& b) {
sort(a.begin(), a.end(), greater<int>());
sort(b.begin(), b.end(), greater<int>());
int res = 0;
auto ai = a.begin(), bi = b.begin();
while (bi != b.end())
if (*ai > *bi)
res++, ai++, bi++;
else
bi++;
return res;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public int solve(int[] a, int[] b) {
TreeMap<Integer, Integer> map = new TreeMap<>();
for (int v : a) {
map.put(v, map.getOrDefault(v, 0) + 1);
}
int ret = 0;
for (int v : b) {
Integer find = map.higherKey(v);
if (find == null) {
continue;
}
map.put(find, map.get(find) - 1);
if (map.get(find) == 0) {
map.remove(find);
}
ret++;
}
return ret;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, a, b):
a = sorted(a)
b = sorted(b)
c = 0
while a and b:
while b and b[-1] >= a[-1]:
b.pop()
if b:
a.pop()
b.pop()
c += 1
return c
```

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