**Number of Non-Overlapping Sublists With Sum of Target - Google Top Interview Questions**

### Problem Statement :

You are given a list of integers nums and an integer target. Return the maximum number of non-overlapping, non-empty sublists that exist such that each sublist's sum is target. Constraints 0 ≤ n ≤ 100,000 where n is the length of nums Example 1 Input nums = [4, 3, 7, 5, -3, 10] target = 7 Output 3 Explanation We can have [4, 3], [7] and [-3, 10]

### Solution :

` ````
Solution in C++ :
int solve(vector<int>& nums, int target) {
unordered_set<int> m{0};
int ans = 0;
for (int i = 0, s = 0; i < nums.size(); i++) {
s += nums[i];
if (m.find(s - target) != m.end()) {
ans++;
m.clear();
}
m.insert(s);
}
return ans;
}
```

` ````
Solution in Python :
class Solution:
def solve(self, nums, target):
s = 0
a = {0: 0}
n = len(nums)
b = [0] * (n + 1)
for i, x in enumerate(nums):
s += x
b[i + 1] = b[i]
if s - target in a:
b[i + 1] = max(b[i + 1], b[a[s - target]] + 1)
a[s] = i + 1
return b[n]
```

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