Number of Non-Overlapping Sublists With Sum of Target - Google Top Interview Questions


Problem Statement :


You are given a list of integers nums and an integer target. 

Return the maximum number of non-overlapping, non-empty sublists that exist such that each sublist's sum is target.

Constraints

0 ≤ n ≤ 100,000 where n is the length of nums

Example 1

Input

nums = [4, 3, 7, 5, -3, 10]

target = 7

Output

3

Explanation

We can have [4, 3], [7] and [-3, 10]


Solution :



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                        Solution in C++ :

int solve(vector<int>& nums, int target) {
    unordered_set<int> m{0};
    int ans = 0;
    for (int i = 0, s = 0; i < nums.size(); i++) {
        s += nums[i];
        if (m.find(s - target) != m.end()) {
            ans++;
            m.clear();
        }
        m.insert(s);
    }
    return ans;
}
                    




                        Solution in Python : 
                            
class Solution:
    def solve(self, nums, target):
        s = 0
        a = {0: 0}
        n = len(nums)
        b = [0] * (n + 1)
        for i, x in enumerate(nums):
            s += x
            b[i + 1] = b[i]
            if s - target in a:
                b[i + 1] = max(b[i + 1], b[a[s - target]] + 1)
            a[s] = i + 1
        return b[n]


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