**Minimum Swaps 2**

### Problem Statement :

You are given an unordered array consisting of consecutive integers [1, 2, 3, ..., n] without any duplicates. You are allowed to swap any two elements. Find the minimum number of swaps required to sort the array in ascending order. Example arr = [ 7 , 1 , 3 , 2, 4 , 5, 6 ] Perform the following steps: i arr swap (indices) 0 [7, 1, 3, 2, 4, 5, 6] swap (0,3) 1 [2, 1, 3, 7, 4, 5, 6] swap (0,1) 2 [1, 2, 3, 7, 4, 5, 6] swap (3,4) 3 [1, 2, 3, 4, 7, 5, 6] swap (4,5) 4 [1, 2, 3, 4, 5, 7, 6] swap (5,6) 5 [1, 2, 3, 4, 5, 6, 7] It took 5 swaps to sort the array. Function Description Complete the function minimumSwaps in the editor below. minimumSwaps has the following parameter(s): int arr[n]: an unordered array of integers Returns int: the minimum number of swaps to sort the array Input Format The first line contains an integer, n, the size of arr . The second line contains n space-separated integers arr[ i ] . Constraints 1 <= n <= 10^5 1 <= arr[i] <= n Sample Input 0 4 4 3 1 2 Sample Output 0 3

### Solution :

` ````
Solution in C++ :
In C++ :
vector<int>v[100003];
bool visit[100003];
int dfs(int i)
{
visit[i] = true;
int z = 1;
for(auto x: v[i])
if(!visit[x])
z += dfs(x);
return z;
}
int minimumSwaps(vector<int> A) {
for(int i = 0; i < A.size(); ++i )
v[i].push_back(A[i]-1), v[A[i]-1].push_back(i);
int c = 0;
for(int i = 0; i < A.size(); ++i)
{
if(!visit[i])
c += dfs(i) - 1;
}
return c;
}
```

` ````
Solution in Java :
In Java :
static int minimumSwaps(int[] a) {
int swap=0;
for(int i=0;i<a.length;i++){
if(i+1!=a[i]){
int t=i;
while(a[t]!=i+1){
t++;
}
int temp=a[t];
a[t]=a[i];
a[i]=temp;
swap++;
}
}
return swap;
}
```

` ````
Solution in Python :
In Python3 :
def minimumSwaps(arr):
ref_arr = sorted(arr)
index_dict = {v: i for i,v in enumerate(arr)}
swaps = 0
for i,v in enumerate(arr):
correct_value = ref_arr[i]
if v != correct_value:
to_swap_ix = index_dict[correct_value]
arr[to_swap_ix],arr[i] = arr[i], arr[to_swap_ix]
index_dict[v] = to_swap_ix
index_dict[correct_value] = i
swaps += 1
return swaps
```

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