Minimum Absolute Difference in an Array


Problem Statement :


The absolute difference is the positive difference between two values a and b, is written | a - b | or | b - a |  and they are equal. If a = 3 and  b = 20,  | 3 - 2 | = | 2 - 3 | = 1 . Given an array of integers, find the minimum absolute difference between any two elements in the array.


Function Description

Complete the minimumAbsoluteDifference function in the editor below. It should return an integer that represents the minimum absolute difference between any pair of elements.

minimumAbsoluteDifference has the following parameter(s):

int arr[n]: an array of integers
Returns

int: the minimum absolute difference found
Input Format

The first line contains a single integer n, the size of arr.
The second line contains n space-separated integers,  arr [ i ].

Constraints

2  <=  n   <=   10^5
- 10^9   <=   arr[ i ]   <=  10^9


Sample Input 0

3
3 -7 0
Sample Output 0

3


Solution :



title-img 


                            Solution in C :

In  C :





#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int cmpfunc (const void * a, const void * b)
{
   return ( *(int*)a - *(int*)b );
}

int main(){
    int n,min,i; 
    scanf("%d",&n);
    int a[n];
    for(i=0;i<n;i++){
        scanf("%d",&a[i]);
    }
    qsort(a, n, sizeof(int), cmpfunc);
    min=a[1]-a[0];
    for(i=0;i<n-1;i++){
        if(min>(a[i+1]-a[i])){
            min=(a[i+1]-a[i]);
        }
    }
    printf("%d",min);
    return 0;
}
                        


                        Solution in C++ :

In  C++ :




#include<bits/stdc++.h>

using namespace std;

int main(){
    int n;
    cin >> n;
    int a[n];
    for(int i = 0; i < n; i++){
        cin >> a[i];
    }
    sort(a, a + n);
    int ans = 2000000001;
    for(int i = 1; i < n; i++){
        if(a[i] - a[i - 1] < ans){
            ans = a[i] - a[i - 1];
        }
    }
    cout << ans;
}
                    


                        Solution in Java :

In  Java :




import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int[] a = new int[n];
        for(int a_i=0; a_i < n; a_i++){
            a[a_i] = in.nextInt();
        }
        Arrays.sort(a);
        int minimum=999999999;
        for(int i = 1; i  <  (a.length - 1); i++){
         int temp = Math.abs(a[i+1] - a[i]);
         if (temp  <  minimum)
            minimum = temp;
      }
        // your code goes here
        System.out.println(minimum);
    }
}
                    


                        Solution in Python : 
                            
In Python3 :




#!/bin/python3

import sys


n = int(input().strip())
a = list(map(int, input().strip().split(' ')))
# your code goes here
a.sort()
m=a[-1]-a[0]
for i in range(1,n):
    if a[i]-a[i-1]<m:
        m=a[i]-a[i-1]
print(m)


View More Similar Problems

Array Manipulation

Starting with a 1-indexed array of zeros and a list of operations, for each operation add a value to each of the array element between two given indices, inclusive. Once all operations have been performed, return the maximum value in the array. Example: n=10 queries=[[1,5,3], [4,8,7], [6,9,1]] Queries are interpreted as follows: a b k 1 5 3 4 8 7 6 9 1 Add the valu

View Solution →

Print the Elements of a Linked List

This is an to practice traversing a linked list. Given a pointer to the head node of a linked list, print each node's data element, one per line. If the head pointer is null (indicating the list is empty), there is nothing to print. Function Description: Complete the printLinkedList function in the editor below. printLinkedList has the following parameter(s): 1.SinglyLinkedListNode

View Solution →

Insert a Node at the Tail of a Linked List

You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Input Format: You have to complete the SinglyLink

View Solution →

Insert a Node at the head of a Linked List

Given a pointer to the head of a linked list, insert a new node before the head. The next value in the new node should point to head and the data value should be replaced with a given value. Return a reference to the new head of the list. The head pointer given may be null meaning that the initial list is empty. Function Description: Complete the function insertNodeAtHead in the editor below

View Solution →

Insert a node at a specific position in a linked list

Given the pointer to the head node of a linked list and an integer to insert at a certain position, create a new node with the given integer as its data attribute, insert this node at the desired position and return the head node. A position of 0 indicates head, a position of 1 indicates one node away from the head and so on. The head pointer given may be null meaning that the initial list is e

View Solution →

Delete a Node

Delete the node at a given position in a linked list and return a reference to the head node. The head is at position 0. The list may be empty after you delete the node. In that case, return a null value. Example: list=0->1->2->3 position=2 After removing the node at position 2, list'= 0->1->-3. Function Description: Complete the deleteNode function in the editor below. deleteNo

View Solution →