Minimum Absolute Difference in an Array


Problem Statement :


The absolute difference is the positive difference between two values a and b, is written | a - b | or | b - a |  and they are equal. If a = 3 and  b = 20,  | 3 - 2 | = | 2 - 3 | = 1 . Given an array of integers, find the minimum absolute difference between any two elements in the array.


Function Description

Complete the minimumAbsoluteDifference function in the editor below. It should return an integer that represents the minimum absolute difference between any pair of elements.

minimumAbsoluteDifference has the following parameter(s):

int arr[n]: an array of integers

Returns

int: the minimum absolute difference found


Input Format

The first line contains a single integer n, the size of arr.
The second line contains n space-separated integers,  arr [ i ].

Constraints

2  <=  n   <=   10^5
- 10^9   <=   arr[ i ]   <=  10^9


Sample Input 0

3
3 -7 0

Sample Output 0

3


Solution :



title-img 


                            Solution in C :

In  C  :






#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int cmpfunc (const void * a, const void * b)
{
   return ( *(int*)a - *(int*)b );
}

int main(){
    int n,min,i; 
    scanf("%d",&n);
    int a[n];
    for(i=0;i<n;i++){
        scanf("%d",&a[i]);
    }
    qsort(a, n, sizeof(int), cmpfunc);
    min=a[1]-a[0];
    for(i=0;i<n-1;i++){
        if(min>(a[i+1]-a[i])){
            min=(a[i+1]-a[i]);
        }
    }
    printf("%d",min);
    return 0;
}
                        


                        Solution in C++ :

In C++  :







#include<bits/stdc++.h>

using namespace std;

int main(){
    int n;
    cin >> n;
    int a[n];
    for(int i = 0; i < n; i++){
        cin >> a[i];
    }
    sort(a, a + n);
    int ans = 2000000001;
    for(int i = 1; i < n; i++){
        if(a[i] - a[i - 1] < ans){
            ans = a[i] - a[i - 1];
        }
    }
    cout << ans;
}
                    


                        Solution in Java :

In  Java :






import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int[] a = new int[n];
        for(int a_i=0; a_i < n; a_i++){
            a[a_i] = in.nextInt();
        }
        Arrays.sort(a);
        int minimum=999999999;
        for(int i = 1; i  <  (a.length - 1); i++){
         int temp = Math.abs(a[i+1] - a[i]);
         if (temp  <  minimum)
            minimum = temp;
      }
        // your code goes here
        System.out.println(minimum);
    }
}
                    


                        Solution in Python : 
                            
In  Python3 :






#!/bin/python3

import sys


n = int(input().strip())
a = list(map(int, input().strip().split(' ')))
# your code goes here
a.sort()
m=a[-1]-a[0]
for i in range(1,n):
    if a[i]-a[i-1]<m:
        m=a[i]-a[i-1]
print(m)


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