**Merging Two Sorted Lists - Amazon Top Interview Questions**

### Problem Statement :

Given two lists of integers a and b sorted in ascending order, merge them into one large sorted list. Constraints 0 ≤ n ≤ 200,000 where n is the length of a 0 ≤ m ≤ 200,000 where m is the length of b Example 1 Input a = [5, 10, 15] b = [3, 8, 9] Output [3, 5, 8, 9, 10, 15]

### Solution :

` ````
Solution in C++ :
vector<int> solve(vector<int>& a, vector<int>& b) {
int an = a.size(), bn=b.size();
int left = 0, right = 0, n=an+bn, k=0;
vector<int> ans(n);
while(left<an && right<bn){
if(a[left]<b[right]) ans[k++] = a[left++];
else ans[k++] = b[right++];
}
while(left<an) ans[k++] = a[left++];
while(right<bn) ans[k++] = b[right++];
return ans;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public int[] solve(int[] a, int[] b) {
int i = 0;
int j = 0;
int[] result = new int[a.length + b.length];
int index = 0;
while (i < a.length || j < b.length) {
int num1 = i < a.length ? a[i] : Integer.MAX_VALUE;
int num2 = j < b.length ? b[j] : Integer.MAX_VALUE;
if (num1 < num2) {
result[index++] = num1;
i++;
} else {
result[index++] = num2;
j++;
}
}
return result;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, l, r):
li, ri, result = 0, 0, []
while li < len(l) and ri < len(r):
if l[li] <= r[ri]:
result.append(l[li])
li += 1
else:
result.append(r[ri])
ri += 1
return result + l[li:] + r[ri:]
```

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