# Linked List Deletion - Amazon Top Interview Questions

### Problem Statement :

```Given a singly linked list node, and an integer target, return the same linked list with all nodes whose value is target removed.

Constraints

n ≤ 100,000 where n is the number of nodes in node

Example 1

Input

node = [0, 1, 1, 2]
target = 1

Output

[0, 2]```

### Solution :

```                        ```Solution in C++ :

** Recursive

LLNode* solve(LLNode* node, int target) {
if(not node) return node;
node->next = solve(node->next, target);
return node->val == target ? node->next : node;
}

** Iterative

LLNode* solve(LLNode* head, int target) {
while (node) {
while (node->next && node->next->val == target) {
node->next = node->next->next;
}
node = node->next;
}
}```
```

```                        ```Solution in Java :

import java.util.*;

/**
* class LLNode {
*   int val;
*   LLNode next;
* }
*/
class Solution {
public LLNode solve(LLNode node, int target) {
LLNode prev = node;
LLNode cur = node.next;
while (cur != null) {
LLNode nxt = cur.next;
if (cur.val == target)
prev.next = nxt;
else {
prev = cur;
}
cur = nxt;
}
if (node.val == target)
return node.next;
return node;
}
}```
```

```                        ```Solution in Python :

class Solution:
def solve(self, node, target):
while node != None and node.val == target:
node = node.next
ret = node
while node != None:
while node.next != None and node.next.val == target:
node.next = node.next.next
node = node.next
return ret```
```

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