**Inverted Subtree - Google Top Interview Questions**

### Problem Statement :

A tree is defined to be an inversion of another tree if either: Both trees are null Its left and right children are optionally swapped and its left and right subtrees are inversions. Given binary trees source and target, return whether there's some inversion T of source such that it's a subtree of target. That is, whether there's a node in target that is identically same in values and structure as T including all of its descendants. Constraints n ≤ 12 where n is the number of nodes in target Example 1 Input source = [0, [1, null, [3, null, null]], [2, null, null]] target = [5, [2, null, null], [0, [2, null, null], [1, [3, null, null], null]]] Output True

### Solution :

` ````
Solution in C++ :
bool recur(Tree* source, Tree* target) {
if (!source && !target) return true;
if (!source || !target || source->val != target->val) return false;
return ((recur(source->left, target->left) && recur(source->right, target->right)) ||
(recur(source->left, target->right) && recur(source->right, target->left)));
}
bool solve(Tree* source, Tree* target) {
if (!source && !target) return true;
if (!source || !target) return false;
if (source->val == target->val) {
return (recur(source, target) || solve(source, target->left) ||
solve(source, target->right));
} else {
return (solve(source, target->left) || solve(source, target->right));
}
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public boolean solve(Tree source, Tree target) {
if (target == null)
return source == target;
return isInv(source, target) || solve(source, target.left) || solve(source, target.right);
}
public boolean isInv(Tree s, Tree t) {
if (s == null || t == null)
return s == t;
if (s.val != t.val)
return false;
return isInv(s.left, t.right) && isInv(s.right, t.left)
|| isInv(s.left, t.left) && isInv(s.right, t.right);
}
}
```

` ````
Solution in Python :
# class Tree:
# def __init__(self, val, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def solve(self, source, target):
if not source or not target:
return not source and not target
t = self.isSubtree(target, source)
return t
def isSubtree(self, s, t):
def sametree(s, t):
if not s or not t:
return not s and not t
elif s.val == t.val:
return (sametree(s.left, t.left) and sametree(s.right, t.right)) or (
sametree(s.right, t.left) and sametree(s.left, t.right)
)
else:
return False
if not s:
return False
elif sametree(s, t):
return True
else:
return self.isSubtree(s.right, t) or self.isSubtree(s.left, t)
```

## View More Similar Problems

## Is This a Binary Search Tree?

For the purposes of this challenge, we define a binary tree to be a binary search tree with the following ordering requirements: The data value of every node in a node's left subtree is less than the data value of that node. The data value of every node in a node's right subtree is greater than the data value of that node. Given the root node of a binary tree, can you determine if it's also a

View Solution →## Square-Ten Tree

The square-ten tree decomposition of an array is defined as follows: The lowest () level of the square-ten tree consists of single array elements in their natural order. The level (starting from ) of the square-ten tree consists of subsequent array subsegments of length in their natural order. Thus, the level contains subsegments of length , the level contains subsegments of length , the

View Solution →## Balanced Forest

Greg has a tree of nodes containing integer data. He wants to insert a node with some non-zero integer value somewhere into the tree. His goal is to be able to cut two edges and have the values of each of the three new trees sum to the same amount. This is called a balanced forest. Being frugal, the data value he inserts should be minimal. Determine the minimal amount that a new node can have to a

View Solution →## Jenny's Subtrees

Jenny loves experimenting with trees. Her favorite tree has n nodes connected by n - 1 edges, and each edge is ` unit in length. She wants to cut a subtree (i.e., a connected part of the original tree) of radius r from this tree by performing the following two steps: 1. Choose a node, x , from the tree. 2. Cut a subtree consisting of all nodes which are not further than r units from node x .

View Solution →## Tree Coordinates

We consider metric space to be a pair, , where is a set and such that the following conditions hold: where is the distance between points and . Let's define the product of two metric spaces, , to be such that: , where , . So, it follows logically that is also a metric space. We then define squared metric space, , to be the product of a metric space multiplied with itself: . For

View Solution →## Array Pairs

Consider an array of n integers, A = [ a1, a2, . . . . an] . Find and print the total number of (i , j) pairs such that ai * aj <= max(ai, ai+1, . . . aj) where i < j. Input Format The first line contains an integer, n , denoting the number of elements in the array. The second line consists of n space-separated integers describing the respective values of a1, a2 , . . . an .

View Solution →