Java If-Else


Problem Statement :


In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Wikipedia if-else flow chart

Source: Wikipedia

Task
Given an integer, n, perform the following conditional actions:

If  is odd, print Weird
If  is even and in the inclusive range of 2 to 5, print Not Weird
If  is even and in the inclusive range of 6 to 20 , print Weird
If  is even and greater than 20 , print Not Weird
Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, n.

Constraints
1 <= n <=100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.



Solution :



title-img


                            Solution in C :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int N = in.nextInt();
        if(N%2==1)
            System.out.println("Weird");
        else
            {
            if(N>=2&&N<=5)
                System.out.println("Not Weird");
            else if(N<=20)
                System.out.println("Weird");
                else
                System.out.println("Not Weird");
        }
    }
}
                        








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