**Java If-Else**

### Problem Statement :

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow: Wikipedia if-else flow chart Source: Wikipedia Task Given an integer, n, perform the following conditional actions: If is odd, print Weird If is even and in the inclusive range of 2 to 5, print Not Weird If is even and in the inclusive range of 6 to 20 , print Weird If is even and greater than 20 , print Not Weird Complete the stub code provided in your editor to print whether or not is weird. Input Format A single line containing a positive integer, n. Constraints 1 <= n <=100 Output Format Print Weird if the number is weird; otherwise, print Not Weird.

### Solution :

` ````
Solution in C :
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int N = in.nextInt();
if(N%2==1)
System.out.println("Weird");
else
{
if(N>=2&&N<=5)
System.out.println("Not Weird");
else if(N<=20)
System.out.println("Weird");
else
System.out.println("Not Weird");
}
}
}
```

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