**Finding the Percentage**

### Problem Statement :

The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal. Example: marks key: value pairs are 'alpha': [20,30,40] 'beta': [30,50,70] query_name = 'beta' The query_name is 'beta'. beta's average score is (20+50+70)/3 = 50. Input Format: The first line contains the integer n, the number of students' records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query. Constraints: 0<=n<=10 0<=marks[i]<=100 length of marks array=3 Output Format: Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

### Solution :

` ````
Solution in C :
if __name__ == '__main__':
n = int(input())
student_marks = {}
for _ in range(n):
line = input().split()
name, scores = line[0], line[1:]
scores = map(float, scores)
student_marks[name] = scores
query_name = input()
marks=0
for i in student_marks[query_name]:
marks=marks+i
avg=marks/3
print("%.2f"%avg)
```

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