Eye and Identity Python
Problem Statement :
identity The identity tool returns an identity array. An identity array is a square matrix with all the main diagonal elements as 1 and the rest as 0. The default type of elements is float. import numpy print numpy.identity(3) #3 is for dimension 3 X 3 #Output [[ 1. 0. 0.] [ 0. 1. 0.] [ 0. 0. 1.]] eye The eye tool returns a 2-D array with 1's as the diagonal and 0's elsewhere. The diagonal can be main, upper or lower depending on the optional parameter k. A positive k is for the upper diagonal, a negative k is for the lower, and a 0 k (default) is for the main diagonal. import numpy print numpy.eye(8, 7, k = 1) # 8 X 7 Dimensional array with first upper diagonal 1. #Output [[ 0. 1. 0. 0. 0. 0. 0.] [ 0. 0. 1. 0. 0. 0. 0.] [ 0. 0. 0. 1. 0. 0. 0.] [ 0. 0. 0. 0. 1. 0. 0.] [ 0. 0. 0. 0. 0. 1. 0.] [ 0. 0. 0. 0. 0. 0. 1.] [ 0. 0. 0. 0. 0. 0. 0.] [ 0. 0. 0. 0. 0. 0. 0.]] print numpy.eye(8, 7, k = -2) # 8 X 7 Dimensional array with second lower diagonal 1. Task: Your task is to print an array of size N X M with its main diagonal elements as 1's and 0s everywhere else. Note In order to get alignment correct, please insert the line numpy.set_printoptions(legacy='1.13) below the numpy import. Input Format: A single line containing the space separated values of N and M. N denotes the rows. M denotes the columns. Output Format: Print the desired N X M array.
Solution :
Solution in C :
#the complete code as requored for the hackerrank challenge
import numpy
n,m=map(int,input().split())
print(str(numpy.eye(n, m,k=0)).replace('0',' 0').replace('1',' 1'))
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