Java Exception Handling (Try-catch)


Problem Statement :


Exception handling is the process of responding to the occurrence, during computation, of exceptions – anomalous or exceptional conditions requiring special processing – often changing the normal flow of program execution. (Wikipedia)

Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.

This problem will test your knowledge on try-catch block.

You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if y is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.


Solution :



title-img 


                            Solution in C :

import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        
        try {
            int x = scan.nextInt();
            int y = scan.nextInt();
            System.out.println(x / y);
        } 
        catch(InputMismatchException e) {
            // ensure that "java.util.InputMismatchException" is printed only.
            System.out.println(e.getClass().toString().replaceFirst("class ", ""));
        }
        catch(ArithmeticException e) {
            // Print exception
            System.out.println(e);
        }
        scan.close();
    }
}








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