**Java Exception Handling (Try-catch)**

### Problem Statement :

Exception handling is the process of responding to the occurrence, during computation, of exceptions – anomalous or exceptional conditions requiring special processing – often changing the normal flow of program execution. (Wikipedia) Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs. This problem will test your knowledge on try-catch block. You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if y is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.

### Solution :

` ````
Solution in C :
import java.util.*;
public class Solution {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
try {
int x = scan.nextInt();
int y = scan.nextInt();
System.out.println(x / y);
}
catch(InputMismatchException e) {
// ensure that "java.util.InputMismatchException" is printed only.
System.out.println(e.getClass().toString().replaceFirst("class ", ""));
}
catch(ArithmeticException e) {
// Print exception
System.out.println(e);
}
scan.close();
}
}
```

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