Create Largest Number From a List - Amazon Top Interview Questions


Problem Statement :


Given a list of integers nums, rearrange its order to form the largest possible integer and return it as a string.

Constraints

n ≤ 1,000 where n is the length of nums

nums[i] ≤ 1,000

Example 1

Input

nums = [10, 7, 76, 415]

Output

"77641510"

Example 2

Input

nums = [961, 745, 331, 794, 923]

Output

"961923794745331"

Example 3

Input

nums = [45, 14, 70, 67, 95]

Output

"9570674514"

Example 4

Input

nums = [70, 5, 94, 18, 78]

Output

"947870518"



Solution :



title-img




                        Solution in C++ :

string solve(vector<int>& _nums) {
    // if i have two numbers
    // i can try both the ways to combine them
    // and select the larger way!
    vector<string> nums;
    for (const int& num : _nums) {
        nums.push_back(to_string(num));
    }

    // now i just sort these to give the biggest value
    sort(nums.begin(), nums.end(), [](const string& a, const string& b) {
        string ab = a + b, ba = b + a;
        return ab > ba;
    });

    string res = "";
    for (const string& num : nums) {
        res += num;
    }

    return res;
}
                    


                        Solution in Java :

import java.util.*;
import java.util.stream.Collectors;

class Solution {
    public String solve(int[] nums) {
        return Arrays.stream(nums)
            .mapToObj(String::valueOf)
            .sorted(Collections.reverseOrder((s1, s2) -> (s1 + s2).compareTo(s2 + s1)))
            .collect(Collectors.joining());
    }
}
                    


                        Solution in Python : 
                            
class Number:
    def __init__(self, n):
        self.n = str(n)

    def __lt__(self, other):
        return self.n + other.n > other.n + self.n

    def __str__(self):
        return self.n

class Solution:
    def solve(self, nums):
        return ''.join(map(str, sorted(map(Number, nums))))
                    


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