Contained Interval - Amazon Top Interview Questions
Problem Statement :
You are given a two-dimensional list of integers intervals where each element is an inclusive interval [start, end]. Return whether there's an interval which contains another interval.
Constraints
n ≤ 100,000 where n is the length of intervals.
Example 1
Input
intervals = [
[1, 3],
[4, 10],
[4, 8],
[9, 9]
]
Output
True
Explanation
[4, 10] contains [4, 8].
Example 2
Input
intervals = [
[1, 3],
[4, 10],
[7, 12]
]
Output
False
Explanation
No interval completely contains another.
Solution :
Solution in C++ :
bool solve(vector<vector<int>>& intervals) {
sort(intervals.begin(), intervals.end());
for (int i = 1; i < intervals.size(); i++) {
if (intervals[i][0] == intervals[i - 1][0]) {
return true;
} else {
if (intervals[i][1] <= intervals[i - 1][1]) {
return true;
}
}
}
return false;
}
Solution in Java :
import java.util.*;
class Solution {
public boolean solve(int[][] intervals) {
Arrays.sort(intervals, new java.util.Comparator<int[]>() {
public int compare(int[] a, int[] b) {
return Integer.compare(a[0], b[0]);
}
});
for (int i = 1; i < intervals.length; i++) {
if (intervals[i - 1][0] == intervals[i][0] || intervals[i - 1][1] >= intervals[i][1])
return true;
}
return false;
}
}
Solution in Python :
class Solution:
def solve(self, intervals):
if not intervals:
return False
intervals.sort(key=lambda x: x[1])
pa, pb = intervals[0]
for i in range(1, len(intervals)):
a, b = intervals[i]
if (pa >= a and pb <= b) or (pa <= a and pb >= b):
return True
pa, pb = a, b
return False
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