**Contained Interval - Amazon Top Interview Questions**

### Problem Statement :

You are given a two-dimensional list of integers intervals where each element is an inclusive interval [start, end]. Return whether there's an interval which contains another interval. Constraints n ≤ 100,000 where n is the length of intervals. Example 1 Input intervals = [ [1, 3], [4, 10], [4, 8], [9, 9] ] Output True Explanation [4, 10] contains [4, 8]. Example 2 Input intervals = [ [1, 3], [4, 10], [7, 12] ] Output False Explanation No interval completely contains another.

### Solution :

` ````
Solution in C++ :
bool solve(vector<vector<int>>& intervals) {
sort(intervals.begin(), intervals.end());
for (int i = 1; i < intervals.size(); i++) {
if (intervals[i][0] == intervals[i - 1][0]) {
return true;
} else {
if (intervals[i][1] <= intervals[i - 1][1]) {
return true;
}
}
}
return false;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public boolean solve(int[][] intervals) {
Arrays.sort(intervals, new java.util.Comparator<int[]>() {
public int compare(int[] a, int[] b) {
return Integer.compare(a[0], b[0]);
}
});
for (int i = 1; i < intervals.length; i++) {
if (intervals[i - 1][0] == intervals[i][0] || intervals[i - 1][1] >= intervals[i][1])
return true;
}
return false;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, intervals):
if not intervals:
return False
intervals.sort(key=lambda x: x[1])
pa, pb = intervals[0]
for i in range(1, len(intervals)):
a, b = intervals[i]
if (pa >= a and pb <= b) or (pa <= a and pb >= b):
return True
pa, pb = a, b
return False
```

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