Contained Interval - Amazon Top Interview Questions


Problem Statement :


You are given a two-dimensional list of integers intervals where each element is an inclusive interval [start, end]. Return whether there's an interval which contains another interval.

Constraints

n ≤ 100,000 where n is the length of intervals.

Example 1

Input

intervals = [
    [1, 3],
    [4, 10],
    [4, 8],
    [9, 9]
]


Output
True


Explanation
[4, 10] contains [4, 8].

Example 2

Input
intervals = [
    [1, 3],
    [4, 10],
    [7, 12]
]


Output
False


Explanation
No interval completely contains another.


Solution :



title-img 




                        Solution in C++ :

bool solve(vector<vector<int>>& intervals) {
    sort(intervals.begin(), intervals.end());
    for (int i = 1; i < intervals.size(); i++) {
        if (intervals[i][0] == intervals[i - 1][0]) {
            return true;
        } else {
            if (intervals[i][1] <= intervals[i - 1][1]) {
                return true;
            }
        }
    }
    return false;
}
                    


                        Solution in Java :

import java.util.*;

class Solution {
    public boolean solve(int[][] intervals) {
        Arrays.sort(intervals, new java.util.Comparator<int[]>() {
            public int compare(int[] a, int[] b) {
                return Integer.compare(a[0], b[0]);
            }
        });
        for (int i = 1; i < intervals.length; i++) {
            if (intervals[i - 1][0] == intervals[i][0] || intervals[i - 1][1] >= intervals[i][1])
                return true;
        }
        return false;
    }
}
                    


                        Solution in Python : 
                            
class Solution:
    def solve(self, intervals):

        if not intervals:
            return False
        intervals.sort(key=lambda x: x[1])
        pa, pb = intervals[0]
        for i in range(1, len(intervals)):
            a, b = intervals[i]
            if (pa >= a and pb <= b) or (pa <= a and pb >= b):
                return True
            pa, pb = a, b
        return False


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