# Cats and a Mouse

### Problem Statement :

```Two cats and a mouse are at various positions on a line. You will be given their starting positions. Your task is to determine which cat will reach the mouse first, assuming the mouse does not move and the cats travel at equal speed. If the cats arrive at the same time, the mouse will be allowed to move and it will escape while they fight.

You are given q queries in the form of x, y, and z representing the respective positions for cats A and B, and for mouse C. Complete the function catAndMouse to return the appropriate answer to each query, which will be printed on a new line.

If cat A catches the mouse first, print Cat A.
If cat B catches the mouse first, print Cat B.
If both cats reach the mouse at the same time, print Mouse C as the two cats fight and mouse escapes.

Example
x = 2
y = 5
z = 4

The cats are at positions 2 (Cat A) and 5 (Cat B), and the mouse is at position 4. Cat B, at position 5 will arrive first since it is only 1 unit away while the other is 2 units away. Return 'Cat B'.

Function Description

Complete the catAndMouse function in the editor below.

catAndMouse has the following parameter(s):

int x: Cat A's position
int y: Cat B's position
int z: Mouse C's position

Returns

string: Either 'Cat A', 'Cat B', or 'Mouse C'

Input Format

The first line contains a single integer, q, denoting the number of queries.
Each of the q subsequent lines contains three space-separated integers describing the respective values of x (cat A's location), y (cat B's location), and z (mouse C's location).

Constraints
1 <= q <= 100
1 <= x,y,z <= 100```

### Solution :

```                            ```Solution in C :

python 3  :

#!/bin/python3

import sys

q = int(input().strip())
for a0 in range(q):
x,y,z = input().strip().split(' ')
x,y,z = [int(x),int(y),int(z)]

if abs(x - z) < abs(y - z):
print('Cat A')
elif abs(x - z) > abs(y - z):
print('Cat B')
else:
print('Mouse C')

java  :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int q = in.nextInt();
for(int a0 = 0; a0 < q; a0++){
int x = in.nextInt();
int y = in.nextInt();
int z = in.nextInt();

int dist = Math.abs(x-z);
int dist2 = Math.abs(y-z);
if (dist < dist2) System.out.println("Cat A");
else if (dist > dist2) System.out.println("Cat B");
else System.out.println("Mouse C");
}
}
}

C++  :

#include <bits/stdc++.h>

using namespace std;

int main()
{
int Q;
scanf("%d", &Q);
while(Q--)
{
int x, y, z;
scanf("%d%d%d", &x, &y, &z);
x=abs(x-z);
y=abs(y-z);
if(x==y)
printf("Mouse C\n");
else if(x<y)
printf("Cat A\n");
else
printf("Cat B\n");
}
return 0;
}

C  :

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
int q;
scanf("%d",&q);
for(int a0 = 0; a0 < q; a0++){
int x;
int y;
int z;
scanf("%d %d %d",&x,&y,&z);
int a = abs(x - z);
int b = abs(y - z);
if (a < b) printf("Cat A\n");
else if (b < a) printf("Cat B\n");
else printf("Mouse C\n");
}
return 0;
}```
```

## Delete a Node

Delete the node at a given position in a linked list and return a reference to the head node. The head is at position 0. The list may be empty after you delete the node. In that case, return a null value. Example: list=0->1->2->3 position=2 After removing the node at position 2, list'= 0->1->-3. Function Description: Complete the deleteNode function in the editor below. deleteNo

## Print in Reverse

Given a pointer to the head of a singly-linked list, print each data value from the reversed list. If the given list is empty, do not print anything. Example head* refers to the linked list with data values 1->2->3->Null Print the following: 3 2 1 Function Description: Complete the reversePrint function in the editor below. reversePrint has the following parameters: Sing

Given the pointer to the head node of a linked list, change the next pointers of the nodes so that their order is reversed. The head pointer given may be null meaning that the initial list is empty. Example: head references the list 1->2->3->Null. Manipulate the next pointers of each node in place and return head, now referencing the head of the list 3->2->1->Null. Function Descriptio